Ch. 6.1 #7-49 odd
Ch. 6.1 #7-49 odd
Ch. 6.1 #7-49 odd
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c) 60.64% of the area under the distribution curve lies to the right of it.<br />
Using the negative z table, area = 1 – 0.6064 = 0.3936. Hence Z=- 0.27.<br />
<strong>49</strong>) Find two z values, one positive and one negative, so that the areas in the two tails total the<br />
following values.<br />
a) 5%<br />
For total area = 0.05, there will be area = 0.025 in each tail. The z scores are 1.96.<br />
b) 10%<br />
For total area =0.10, there will be area = 0.05 in each tail. The z scores are 1.645.
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