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CHAPTER 2: Markov Chains (part 3)

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E i .<br />

Let z i be the proportion of women before she reach E 5 she is single given the initial state is<br />

z 0 = p 01 z 1 + p 05 0<br />

z 1 = p 11 z 1 + p 12 z 2 + p 15 1<br />

z 2 = p 22 z 2 + p 23 z 3 + p 24 z 4 + p 25 0<br />

z 3 = p 32 z 2 + p 33 z 3 + p 35 0<br />

z 4 = p 42 z 2 + p 44 z 4 + p 45 0<br />

z 5 = 0<br />

we have<br />

z 0 = 0.0643, z 1 = 0.0714, z 2 = 0, z 3 = 0z 4 = 0, z 5 = 0<br />

Example [A process with short-term memory, e.g. the weather depends on the past m-days]<br />

We constrain the weather to two states s: sunny, s: cloudy<br />

- - - s c s s c s - -<br />

X n−1 X n X n+1<br />

Suppose that given the weathers in the previous two days, we can predict the weather in the<br />

following day as<br />

sunny (yesterday) + sunny (today) =⇒ sunny (tomorrow) with probability 0.8;<br />

cloudy (tomorrow) with probability 0.2;<br />

cloudy (yesterday)+sunny (today) =⇒ sunny (tomorrow) with probability 0.6;<br />

cloudy (tomorrow) with probability 0.4;<br />

sunny (yesterday)+cloudy (today) =⇒ sunny (tomorrow) with probability 0.4;<br />

cloudy (tomorrow) with probability 0.6;<br />

cloudy (yesterday)+ cloudy (today) =⇒ sunny (tomorrow) with probability 0.1;<br />

cloudy (tomorrow) with probability 0.9;<br />

Let X n be the weather of the n’th day. Then the state space is<br />

S = {s, c}<br />

6

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