Timber Frame Tension Joinery - Timber Frame Engineering Council
Timber Frame Tension Joinery - Timber Frame Engineering Council
Timber Frame Tension Joinery - Timber Frame Engineering Council
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to the dowel and e is the eccentricity of the load; the material thickness and dowel diameter<br />
are t and D, respectively; the positions of the dowel pivot point and plastic hinge point are x<br />
and Z, respectively; the dowel bearing strength of the base material is F e and the bending<br />
yield strength of the dowel is F yb . Equations 3-1 and 3-2 are derived in Appendices A and B,<br />
respectively.<br />
These equations are applied to each yield mode to determine joint capacity. For<br />
instance, the single shear Mode IV has the same type of failure in both the main and side<br />
member. Therefore, Eq. 3-2 can be used for each member. From equilibrium, the yield load<br />
in each member must be equal, and is the following (Thangjitham, 1981):<br />
P=<br />
D<br />
2<br />
2F F<br />
em<br />
⎛ F<br />
31 ⎜ +<br />
⎝ F<br />
yb<br />
em<br />
es<br />
⎞<br />
⎟<br />
⎠<br />
(3-3)<br />
The above equation uses F em and F es for the dowel bearing strength in the main<br />
(thicker) and side (thinner) members, respectively.<br />
The derivation of these equations is based on the assumption that a single, unique<br />
position for the eccentricity can be found and that the resultant of the load for the entire<br />
connection is at this location. Section 3.3 contains an alternative method for calculating the<br />
yield load for Mode IV.<br />
The yield loads for the single shear modes are as follows:<br />
P D t F<br />
I m em<br />
m = ⋅ ⋅ (3-4)<br />
P D t F<br />
I s es<br />
s<br />
= ⋅ ⋅ (3-5)<br />
PII = k1 ⋅D⋅ts ⋅Fes<br />
(3-6)<br />
P<br />
III<br />
= k2<br />
⋅D⋅tm⋅F<br />
m<br />
( 1+ 2⋅R<br />
)<br />
e<br />
em<br />
(3-7)<br />
13