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Timber Frame Tension Joinery - Timber Frame Engineering Council

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Plastic hinges occur in the peg due to bending and are located at points of maximum<br />

moment (see Figure 3-5). This derivation is as follows:<br />

From equilibrium:<br />

x<br />

A<br />

P<br />

= (3-23)<br />

DF<br />

em<br />

For failure to occur, two plastic hinges must occur in the peg. Areas under the shear<br />

diagram give<br />

DF ( a − b) x DF ( d − c)<br />

x<br />

+<br />

2 2<br />

em A es D<br />

= 2 M<br />

(3-24)<br />

p<br />

DFem( a − b)<br />

= P<br />

(3-25)<br />

DF ( d − es<br />

c ) = P<br />

(3-26)<br />

Simplifying Equation 3-24, we obtain<br />

Px<br />

A<br />

+ PxD = 4 M<br />

p<br />

(3-27)<br />

x<br />

D<br />

4M<br />

p<br />

= −x<br />

P<br />

A<br />

(3-28)<br />

Total distance between hinges is<br />

x = x + x<br />

(3-29)<br />

A<br />

D<br />

4M<br />

p<br />

4FybD<br />

x = =<br />

P 6P<br />

3<br />

(3-30)<br />

Substituting Eq. 3-22 into Eq. 3-30 we obtain<br />

x = D<br />

⎛ F<br />

2Fyb⎜1+<br />

⎝ F<br />

3F<br />

em<br />

em<br />

es<br />

⎞<br />

⎟<br />

⎠<br />

(3-31)<br />

As a numerical example, typical values for 1” Red Oak Pegs in Douglas Fir give a<br />

total distance between plastic hinges of 3.0 inches (using F yb = 12,601 psi, F em = 2070 psi,<br />

17

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