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AD Tutorial at the TU Berlin

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Summary: Forward Mode and Reverse Mode<br />

Goal: compute Jacobian J = dF<br />

dx of function F : RN → R M<br />

Forward Mode: J = dF<br />

dx · S, where S = I ∈ RN×N<br />

needs N OPS(F) and MEM(J) ≤ N MEM(F)<br />

Reverse Mode: J = ¯S T · dF<br />

dx<br />

, where S = I ∈ RM×M<br />

OPS(J) ≈ M OPS(F) but MEM(J) ∼ OPS(F)<br />

Rule of Thumb: if 5M < N <strong>the</strong>n reverse mode most likely more efficient,<br />

but only if and only if <strong>the</strong>re is enough RAM!<br />

Partial Solution: can use Checkpointing to obtain logarithmic growth in<br />

<strong>the</strong> memory.<br />

For M ≪ N reverse mode will be <strong>the</strong> method of choice.<br />

Sebastian F. Walter, HU <strong>Berlin</strong> () Not So Short <strong>Tutorial</strong> OnAlgorithmic Differenti<strong>at</strong>ion Wednesday, 04.06.2010 16 / 39

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