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Partial Differential Equations

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∫<br />

I ≤ ε Φ(x − y, t)dy = ε.<br />

R n<br />

1.3 The Heat Equation 21<br />

To estimate J, we note that for x ∈ B(x 0 , δ 2 ) and y ∉ B(x0 , δ), we have<br />

|y − x 0 | ≤ |y − x| + δ 2 ≤ |y − x| + 1 2 |y − x0 |,<br />

i.e. 1 2 |y − x0 | ≤ |x − y|. If ‖g‖ ∞ = sup x∈R n |g(x)|, then we find<br />

δ<br />

δ/2<br />

x 0<br />

y<br />

x<br />

Fig. 1.9.<br />

J ≤ 2‖g‖ ∞<br />

∫<br />

≤ C′<br />

t n 2<br />

∫ ∞<br />

δ<br />

R n \B(x 0 ;δ)<br />

Φ(x − y, t) dy = C t n 2<br />

e − r2<br />

16t r n−1 dr,<br />

∫<br />

R n \B(x 0 ;δ)<br />

e − |x−y|2<br />

4t dy ≤ C t n 2<br />

∫<br />

R n \B(x 0 ;δ)<br />

e − |x0 −y| 2<br />

16t<br />

dy<br />

and the latter integral converges to 0 for t ↘ 0, since for suitable constants c, d > 0, we have (Exercise!)<br />

e − r2<br />

16t<br />

r n−1 ≤ ce − r2<br />

t n dt ∀r ≥ δ.<br />

2<br />

2·10 10 0.002<br />

1·10 10<br />

0.0018<br />

0<br />

0.0016<br />

50 100 0.0014<br />

150<br />

t<br />

200 0.0012<br />

r<br />

250 300 0.001<br />

8·10 10<br />

6·10 10<br />

0.002<br />

4·10 10<br />

2·10 10<br />

0.0018<br />

0<br />

0.0016<br />

50 100 0.0014<br />

150<br />

t<br />

200 0.0012<br />

r<br />

250 300 0.001<br />

Fig. 1.10. The functions e − r2<br />

16t r 3 t − 3 2<br />

and 10 11 e − r2<br />

17t for r ∈ [50, 300] and t ∈ [10 −3 , 2 · 10 −3 ]<br />

Together, we obtain |u(x, t) − g(x 0 )| < 2ε for sufficiently small t, and this is precisely the claim.<br />

Remark 1.3.5. If g ∈ C(R n ) is a bounded, nonnegative and nonvanishing function, then

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