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Jr(x) — g 't1p(x) Ir 7rn(x) . (5 .2 .1 )<br />

Using isospin, (5 .2 .1) become s<br />

— (€/ 2) ( ( x ) Yr. T *~J(x) ) (5 .2 .2 )<br />

or<br />

( g/2<br />

-<br />

,1r2 ) [l1'(x),<br />

( rT + l(x)] . (5 .2 .3 )<br />

The electromagnetic current (4 .4 .3) of the nucleon system i s<br />

Jel ( x ) = J e ( ' p ( x ) Yr p ( x ) ) , (5 .2 .4 )<br />

or, in isospin formalism :<br />

(je/4) DTI(x), Y r (1 + T3 ) V ( x )] . (5 .2 .5 )<br />

From (5 .2 .5) we see that (5 .2 .4) may be decomposed into an isospin scalar an d<br />

an isospin vector (an isoscalar and isovector) :<br />

J S<br />

Jel(x)<br />

(x) + J (x) , (5 .2 .6 )<br />

where<br />

T<br />

r<br />

Jr (x) _ (J e/4) [(x), Yr W(x)]<br />

(5 .2 .7 )<br />

and<br />

JJr ( x ) = (j e /4) [ r(x), Y r T 3 1p (x)7 . (5 .2 .8)<br />

Obviously the current (5 .2 .1) may be considered as another comp<strong>one</strong>nt of (5 .2 .8) ,<br />

so tha t<br />

J (x) = J 2 g/e (+) (x) . (5 .2 .9 )<br />

Unfortunately<br />

r<br />

the electromagnetic nucleon current (5 .2 .4) does not obey a<br />

continuity equation of the form (1 .4 .12) . Howeve r<br />

a Jel<br />

' D<br />

0 (5 .2 .10 )<br />

t<br />

J being define d<br />

J r<br />

(x)<br />

= je Caa(X) ~(x) —<br />

t(x)2'ah))<br />

(5 .2 .11 )<br />

where cp is the compler x pion field in (5 .1 .22) and (5 .1 .23) . By decomposing<br />

the latter field into real and imaginary comp<strong>one</strong>nts, we may write<br />

( O J (x)/2xr ) + ( 2/d xr )(JJ (x) + , (x) ) = 0 . (5 .2 .12)<br />

Thus reach term in (5 .2 .12) is conserved . We assume that the <strong>interaction</strong> which w e<br />

are considering is invariant under rotations in isospin space, and hence othe r<br />

comp<strong>one</strong>nts of the second term in (5 .2 .12) will also be conserved :<br />

J<br />

( a fix) (JRV (+) ( x ) + ,2j (4) (x) ) = 0 .<br />

(5 .2 .13 )

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