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We are thus forced to conclude that only antineutrinos with positiv e<br />

helicity (r= 2), and only neutrinos with negative helicity (r = 1) may<br />

ever be produced . We may therefore reduce our usual four-comp<strong>one</strong>n t<br />

neutrino spinor to a two-comp<strong>one</strong>nt <strong>one</strong> . This is known as the<br />

neutrino hypothesis' .<br />

'two-comp<strong>one</strong>n t<br />

We now discuss the experimental determination of the neutrin o<br />

helicity (69) . In a decay of the form<br />

A(0) + e >B(1 )-+v >C(O') + f , (3 .8 .6 )<br />

we see that, by angular momentum conservation, 1 the nucleus B must have<br />

a spin opposite to that of the emitted neutrino . Furthermore, when th e<br />

excited nuclide B returns to the ground-state C, the circular polarizatio n<br />

of the decay photon will be by cos e), where e is the angle between<br />

the neutrino and photon momentum vectors . In order to select only thos e<br />

gamma rays which are emitted in a direction opposite to their associate d<br />

neutrinos, we may employ the phenomenon of nuclear resonance scattering .<br />

When a photon is emitted or absorbed by a nucleus, the latter recoils wit h<br />

energy n^g/M<br />

. Thus, when a photon is absorbed, the energy available fo r<br />

excitation is only E O(l - EO /M) . In order to make resonance possible ,<br />

extra energy, amounting to that lost in the nuclear recoil, must be supplied t o<br />

the photon . This occurs if the decaying nucleus has already recoile d<br />

in a direction opposite to that induced by gamma-ray emission . Such an<br />

extra recoil could be provided by the emission of a neutrino whos e<br />

direction of motion was precisely opposite to that of the photon .<br />

The Doppler shift in the gamma-ray energy caused by the nuclear recoi l<br />

is given b y<br />

L'_\E _ (EO Ev cose)/ii , (3 .8 .7a )<br />

and hence the total energy for excitation transferred by the gamma ray<br />

will be<br />

E EO t (E0 Ev cos e )/M - ED/i . (3 .8 .7b )<br />

We now deduce that the condition for resonant absorption i s<br />

Ev case = EO • (3 .8 .7c )<br />

1 . Obviously we assume that any electrons captured from the atomic K shel l<br />

will be s-wave .

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