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neutrinos is 10 22 .5 * 2 .5 (22) . The latter agrees better with experimenta l<br />

evidence than the former, but since it is impossible to observe the two<br />

electrons in (4 .5 .4)<br />

experimentally, this experiment does not rule out lepto n<br />

number violation . However, the figures quoted above set an upper limit on<br />

the lepton number violating amplitude in double beta decay of 3 x 1 0-3 .<br />

More direct evidence for lepton conservation comes from a study o f<br />

antineutrino capture . The antineutrino in beta decay has a lepton number of -1 ,<br />

and hence the proces s<br />

ve + (z, A) >(z+1, A) + e (4 .5 .5 )<br />

cannot occur . However ,<br />

ve + (Z, A) (Z - 1, A) + e t (4 .5 .6 )<br />

does not violate lepton number conservation . Antineutrinos from atomic pile s<br />

have been observed to produce positrons according to (4 .5 .6) (23), and<br />

no electrons have been found due to the <strong>interaction</strong> of antineutrinos an d<br />

01 37 .<br />

We now consider a possible alternative assignment of lepton numbe r<br />

than that discussed above . The electron, positron, e-neutrino and anti-e-neutrin o<br />

retain the same lepton number as before, but the lepton number of the muon<br />

and associated particles change sign, according to the suggestion o f<br />

Konopinski and Mahmoud (24) . Thus the t~<br />

is now a lepton, while the<br />

e -<br />

becomes an antilepton . The four types of neutrinos still remain, but, sinc e<br />

both the v e<br />

and the ve are left-handed (i .e . they have a helicity of -1), th e<br />

ve is now a left-handed lepton state, while the y r is a left-handed antilepton .<br />

Thus we have dispensed with the need for an electron and muon number . Thi s<br />

means that we may use a single 4-comp<strong>one</strong>nt field to describe the neutrino s<br />

instead of the usual two 2-comp<strong>one</strong>nt <strong>one</strong>s . The latter are separated purel y<br />

because of the existence of muon and electron number . Let (x) and (1)y, (x )<br />

r<br />

be the field operators for the muon and electron neutrinos respectively .<br />

Since we know the helicity or chirality of the states yr and ve , we may write<br />

(1),,r, (x) _ '-( l - Y5)Jv1 ( x ) (4 .5 .7 )<br />

and<br />

q,, (x) +(l + 1 5 )-t (x ) . (4 .5 .8)<br />

Since the only distinction between 1 J,~~(x) and 2~f, ,r (x) now lies in their

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