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introduction-weak-interaction-volume-one

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and from (2 .6 .13) and (2 .6 .14 )<br />

(4 + )t Cp (2 .6 .17 )<br />

Now let us attempt to calculate the value of the commutato r<br />

[4(x) , 4(x')1 ,<br />

(2 .6 .18 )<br />

where x and x' are two position space-time four-vectors . Since two creation<br />

or two destruction operators commute,<br />

[( x ) , 0(xiF<br />

V<br />

o(k)<br />

1<br />

(27) 3 . 2<br />

koz W(~<br />

w(_' )<br />

2<br />

,1<br />

o o<br />

only cross-terms will contribute, and thu s<br />

T<br />

r a(s), a-1(k`)J ejkx-jk x<br />

i (<br />

L<br />

[a t(), a(k')] e ')<br />

d3k (ejk(x-x') _ ejk(x-x') )<br />

,<br />

ko<br />

(2 .6 .19)<br />

anticipating going to the limit of normalization and using the approximation<br />

(2 .2 .10) . We defin e<br />

_ 1<br />

d :<br />

A(x)<br />

k sin itx<br />

(2Tv)3 k W(k)<br />

,<br />

0 0<br />

so tha t<br />

E( x), (x' ;) = j b(x-x' )<br />

From (2 .6 .20) we see that ,6.(x) is a real odd function of x, and is a Lorentz<br />

invariant scalar . Thus<br />

O(_, t = 0 ) -<br />

1 cd 3'~<br />

w(k) sin kX - 0<br />

(2~ ) 3 J<br />

so that the 'equal times' commutator<br />

0 .<br />

Since the Ls, function is a Lorentz invarian t<br />

2s(x) 0 x2 - x2 - t2 > 0 ,<br />

and thus<br />

the 0 function vanishes outside the 'light-c<strong>one</strong> '<br />

(2 .6 .20 )<br />

(2 .6 .21 )<br />

(2 .6 .22)<br />

J x ` -<br />

it( ,<br />

and similarly the commutator in (2 .6 .21) vanishes for points with space-lik e<br />

separation :<br />

(x-x') 2 0 . (2 .6 .26 )<br />

If the commutator (2 .6 .18) was non-vanishing for space-like separated points<br />

x and x', then this would imply that the measurements of the field at two<br />

separated points in space interfered with each other, necessitating a signal<br />

travelling faster than the velocity of light .<br />

upholds the special theory of relativity .<br />

The vanishing commutator thu s

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