13.01.2015 Views

Correspondence of Marcel Riesz with Swedes. Part II. file: Riesz1.tex

Correspondence of Marcel Riesz with Swedes. Part II. file: Riesz1.tex

Correspondence of Marcel Riesz with Swedes. Part II. file: Riesz1.tex

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

0.4. ALFRED LILJESTRÖM 25<br />

After my return from Copenhagen I made some measurements in order to be able to<br />

master numerically fhe top’s special inertia properties. It turned out that one from the<br />

above equation comes to the following more special equation holding for the nutation limits<br />

<strong>of</strong> the top:<br />

1 − q 2 = 2mglAu −<br />

R 2 0<br />

(1 − qu)2<br />

1 − u 2 = 0,<br />

provided one assumes that, at the start, the top has its axis nearly horisontal and there is<br />

no translatory motion.<br />

A simple calculation shows that in this formula the fractal expression for u = q takes<br />

its minimal value 1 − q 2 or exactly the value that linear expression in the formula takes<br />

for u = 0. Geometrically, this means that for large values <strong>of</strong> R 0 , e.g. if the top’s initial<br />

spin is sufficiently large, then the straigt line meets the cubic in two points which lie very<br />

close to the value u = q. This in turn implies that the braking <strong>of</strong> the top <strong>with</strong> some<br />

approximation follows the formula<br />

R z = R 0 cos θ<br />

The nutation theory that I presented in Copenhagen can thus beused to follow in<br />

detail the top’s curious brakning process. It gives likewise a striking verification <strong>of</strong> what<br />

I also said in Copenhagen, among other things, namely that the pivot motion <strong>of</strong> the top<br />

<strong>with</strong> its centre <strong>of</strong> gravity displaced by no means contradicts the existence <strong>of</strong> two nutation<br />

limits, so that the phenomen evoced by you corresponds to the case when both limits<br />

coincide, the straight line being tangent to the cubic.<br />

I understand now very well that you now, after havig taken part <strong>of</strong> my results in<br />

my first letter, gladly want to arrive to them along more elementary paths, because you<br />

find the nutation theory complicated. The attempt to an “elementary theory”, as your<br />

son presented in his letter, and which you refer to, gives me some doubts. To start,<br />

<strong>with</strong>out further ado, from formula R z = R 0 cos θ and then say that one can by “se bort<br />

fra tyngdenutationerne, umiddelbart vise at θ vil variere omtrænt lineært med tiden” 10<br />

(neglect the weight nutations immediately show that θ varies inversely linearly <strong>with</strong> time)<br />

seems to mean that by assuming θ constant one can show that θ varies linearly <strong>with</strong> time.<br />

Moreover, the presentation, it seems me, is based on the misunderstanding that gravity<br />

alone causes the nutations. This is not the case. If one puts the gravity constant g equal<br />

to zero in the nutations equation, then it is only one little term that vanishes, all the other<br />

remain and witnes that the laws <strong>of</strong> natures are such that inertia properties <strong>of</strong> the ball-top<br />

can give rise to complications.<br />

I am tempted to quote Poincaré/’s famous reply to Felix Klein: “Voilà une difficulté<br />

dont on ne triomphe pas en quelques lignes!” (French, Here is a difficulty that one does<br />

not overcome in a few lines!)<br />

10 Editor: This quote is in Danish.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!