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PDF of Lecture Notes - School of Mathematical Sciences

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1. DISTRIBUTION THEORY<br />

Recall standard limit:<br />

(<br />

lim 1 + a ) n<br />

= e<br />

a<br />

n→∞ n<br />

⇒ f T (t) → 1 √<br />

2π<br />

e −t2<br />

2 as k → ∞.<br />

Suppose h : R r → R r is continuously differentiable.<br />

That is,<br />

h(x 1 , x 2 , . . . , x r ) = (h 1 (x 1 , . . . , x r ), h 2 (x 1 , . . . , x r ), . . . , h r (x 1 , . . . , x r )) ,<br />

where each h i (x) is continuously differentiable. Let<br />

⎡<br />

⎤<br />

∂h 1 ∂h 1 ∂h 1<br />

. . .<br />

∂x 1 ∂x 2 ∂x r<br />

∂h 2 ∂h 2 ∂h 2<br />

. . .<br />

∂x<br />

H = 1 ∂x 2 ∂x r<br />

. . . . . .<br />

⎢<br />

⎥<br />

⎣∂h r ∂h r ∂h r<br />

⎦<br />

. . .<br />

∂x 1 ∂x 2 ∂x r<br />

If H is invertible for all x, then ∃ an inverse mapping:<br />

g : R r → R r<br />

g(h(x)) = x.<br />

with property that:<br />

It can be proved that the matrix <strong>of</strong> partial derivatives<br />

( ) ∂gi<br />

G = satisfies G = H −1 .<br />

∂y j<br />

Theorem. 1.8.4<br />

Suppose X 1 , X 2 , . . . , X r have joint <strong>PDF</strong> f X (X 1 , . . . , X r ), and let h, g, G be as above.<br />

If Y = h(X), then Y has joint <strong>PDF</strong><br />

Remark:<br />

f Y (y 1 , y 2 , . . . , y r ) = f X<br />

(<br />

g(y)<br />

)<br />

| det G(y)|<br />

Can sometimes use H −1 instead <strong>of</strong> G, but need to be careful to evaluate H −1 (x) at<br />

x = h −1 (y) = g(y).<br />

40

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