PDF of Lecture Notes - School of Mathematical Sciences
PDF of Lecture Notes - School of Mathematical Sciences
PDF of Lecture Notes - School of Mathematical Sciences
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1. DISTRIBUTION THEORY<br />
Recall standard limit:<br />
(<br />
lim 1 + a ) n<br />
= e<br />
a<br />
n→∞ n<br />
⇒ f T (t) → 1 √<br />
2π<br />
e −t2<br />
2 as k → ∞.<br />
Suppose h : R r → R r is continuously differentiable.<br />
That is,<br />
h(x 1 , x 2 , . . . , x r ) = (h 1 (x 1 , . . . , x r ), h 2 (x 1 , . . . , x r ), . . . , h r (x 1 , . . . , x r )) ,<br />
where each h i (x) is continuously differentiable. Let<br />
⎡<br />
⎤<br />
∂h 1 ∂h 1 ∂h 1<br />
. . .<br />
∂x 1 ∂x 2 ∂x r<br />
∂h 2 ∂h 2 ∂h 2<br />
. . .<br />
∂x<br />
H = 1 ∂x 2 ∂x r<br />
. . . . . .<br />
⎢<br />
⎥<br />
⎣∂h r ∂h r ∂h r<br />
⎦<br />
. . .<br />
∂x 1 ∂x 2 ∂x r<br />
If H is invertible for all x, then ∃ an inverse mapping:<br />
g : R r → R r<br />
g(h(x)) = x.<br />
with property that:<br />
It can be proved that the matrix <strong>of</strong> partial derivatives<br />
( ) ∂gi<br />
G = satisfies G = H −1 .<br />
∂y j<br />
Theorem. 1.8.4<br />
Suppose X 1 , X 2 , . . . , X r have joint <strong>PDF</strong> f X (X 1 , . . . , X r ), and let h, g, G be as above.<br />
If Y = h(X), then Y has joint <strong>PDF</strong><br />
Remark:<br />
f Y (y 1 , y 2 , . . . , y r ) = f X<br />
(<br />
g(y)<br />
)<br />
| det G(y)|<br />
Can sometimes use H −1 instead <strong>of</strong> G, but need to be careful to evaluate H −1 (x) at<br />
x = h −1 (y) = g(y).<br />
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