09.07.2015 Views

Quantum Field Theory

Quantum Field Theory

Quantum Field Theory

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

ψ † ∼ b † + c. To get non-zero overlap with 〈f|, only the b † and c † contribute, for theycreate the nucleon and anti-nucleon from |0〉. We then have∫ ∫ √d 4 xd 3 k 1 d 3 k 2 E⃗q1 E ⃗q2〈f|S |i〉 = −ig 〈0|(2π) 6 √E⃗k1 cE ⃗q2 b ⃗q1 c † ⃗ k1b † ⃗ k2|0〉 e i(q 1+q 2 −p)·x⃗k2= −ig (2π) 4 δ (4) (q 1 + q 2 − p) (3.30)and so we get our first quantum field theory amplitude.Notice that the δ-function puts constraints on the possible decays. In particular, thedecay only happens at all if m ≥ 2M. To see this, we may always boost ourselvesto a reference frame where the meson is stationary, so p = (m, 0, 0, 0). Then thedelta function imposes momentum conservation, telling us that ⃗q 1 = −⃗q 2 and m =2 √ M 2 + |⃗q| 2 .Later you will learn how to turn this quantum amplitude into something more physical,namely the lifetime of the meson. The reason this is a little tricky is that we mustsquare the amplitude to get the probability for decay, which means we get the squareof a δ-function. We’ll explain how to deal with this in Section 3.6 below, and again innext term’s “Standard Model” course.3.3 Wick’s TheoremFrom Dyson’s formula, we want to compute quantities like 〈f|T {H I (x 1 ) . . .H I (x n )} |i〉,where |i〉 and |f〉 are eigenstates of the free theory. The ordering of the operators is fixedby T, time ordering. However, since the H I ’s contain certain creation and annihilationoperators, our life will be much simpler if we can start to move all annihilation operatorsto the right where they can start killing things in |i〉. Recall that this is the definitionof normal ordering. Wick’s theorem tells us how to go from time ordered products tonormal ordered products.3.3.1 An Example: Recovering the PropagatorLet’s start simple. Consider a real scalar field which we decompose in the Heisenbergpicture aswhereφ(x) = φ + (x) + φ − (x) (3.31)∫φ + (x) =∫φ − (x) =d 3 p 1√ a(2π) 3 ⃗p e −ip·x2E⃗pd 3 p(2π) 3 1√2E⃗pa † ⃗p e+ip·x (3.32)– 56 –

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!