Rca1948FrequencyModu.. - The New Jersey Antique Radio Club

298 FREQUENCY MODULATION, Volume IR = V#i8 + # 2 2 + ZEiE 2 cos 6.The angle 8 between the two vectors #1 and E 2 equals the differenceof the two arguments of the sine functions.D D8 = ^- sin 2-Kjxt sin 27r/i (t — 1 ) + a>t .The angle a between R and E 1is given byE 2 sin 8 x sin 8tan 1E x + E 2 cos 8 1 + x cos 1E 2-where x =EiThe law of cosines gives, thereforeej + e 2= V#i2+ £,2 2 + 2£' 1 £' 2cos 8 sinjD a; sin 6,>t + — sin 2-n-fit — tan-1fi 1 + x cos 8) . (21)Since sin a — sin (a — /?) = + 2 cos (a — /J/2) sin /?/2,D8 = 2 — sin irjitf) cos (2-Kjxt — T/xi ) + &tM= 2 COS (2-Kji.t — ,T/xi ) +