12.07.2015 Views

Contents

Contents

Contents

SHOW MORE
SHOW LESS
  • No tags were found...

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

10.11 Generation methods includingperfect fluids 153and has an equation of state µ +3p = 0, then a one-parameter familyof solutions can be generated from this solution. The method relies onthe existence of a twist potential ω ,a = ε abcd ξ d;c ξ b ; for details see §10.3.2above and Stephani (1988). Since the equation of state µ+3p = 0 is ratherunphysical, only very few examples have been discussed for this case, seee.g. Rácz and Zsigrai (1996). For stiff matter µ = p, two more generationmethods are available which we shall discuss now.If the four-velocity is irrotational, it can be written in terms of a scalarfunction σ(z,t) asu n = σ ,n (−σ ,a σ ,a ) −1/2 , (10.105)and Einstein’s field equations for a stiff fluid readR ab =2σ ,a σ ,b , κ 0 p = κ 0 µ = −σ ,n σ ,n (10.106)(Tabensky and Taub 1973). If the metric admits a spacelike hypersurfaceorthogonalKilling vector ξ = ∂ x , it can be written asds 2 =e 2U dx 2 +e −2U γ αβ dx α dx β , α,β =1, 2, 3. (10.107)With respect to (10.107), the field equations read3Rαβ= 2U ,α U ,β +2σ ,α σ ,b , U ;α,α = 0 (10.108)(with ξ n σ ,n =0=ξ n U ,n ), cp. Theorem 18.1. Four-velocity (σ ,a ) and thegradient of U enter in a very symmetric way, and the following theorem(Kroriand Nandy 1984) can easily be read off:Theorem 10.1 If ds 2 =e 2V dx 2 +e −2V γ αβ dx α dx β is a vacuum solutionwith V ,α V α < 0, then (10.107) with U =(1− λ)V , λ = const, is a stifffluid solution with σ =(2λ − λ 2 ) 1/2 V .Unfortunately there are not many non-static solutions with only oneKilling vector (so that in the applications (Krori and Nandy 1984, Baillieand Madsen 1985) of this theorem some seed metrics admit even a G 3 ).Most of the possible seed metrics admit a G 2 , and then a more powerfulmethod is available.If the metric admits two commuting spacelike Killing vectors ∂ x and ∂ y(orthogonally transitive), the line element can be written asds 2 =e M (dz 2 − dt 2 )+W [e −Ψ dy 2 +e Ψ (dx + Ady) 2 ], W > 0, (10.109)cp. §17.1.2. If the four-velocity is orthogonal to the group orbits, it isnecessarily irrotational, so that (10.105) is satisfied. The Bianchi identities

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!