Short Lab Report Examples and Guide

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4. Calculate the photon energy corresponding to the peak in the absorption andemission spectra in the units specified on the report page. (see example on nextpage)a. Answer values correct = +2 ptsb. Proper significant figures and units used = + 2 pts5. In a paragraph or two, explain why the absorption and emission wavelengths aredifferent and why the absorption and emission spectra look similar yet shifted onthe wavelength axis.Fluorescence Experiment: Example Plot.0.10.09λ MAX Abs = 528 nmλ MAX Em = 548 nmAbsorbance0.080.070.060.050.040.030.020.0101.0 µM Rhodamine 6G in water(1.0 cm path)EmissionAbsorbance-0.01400 450 500 550 600 650 700 750 800Wavelength (nm)Fluorescence Experiment : Example Calculations.eV := 1 nm := 10 − 9 ⋅mh := 6.626⋅10 − 34 ⋅J⋅sc 3.00⋅10 8 m:= ⋅sλ 528⋅10 − 9 c:= ⋅mν :=λE:= h⋅νE = 3.765× 10 − 19 J Photon energy in JE⋅ 6.02⋅10 23 − 1⋅mol2.266×10 5 J=molPhoton Energy in J/molE1.602⋅10 − 19 J⋅eV= 2.35eVPhoton Energy in electron volts1λ⋅10 − 7 cm⋅nm= 18939cm − 1Photon Energy in wavenumbers
Jablonski Diagram Page:λ MAX / nmJoulesJoules / molElectron volts (eV)Reciprocal cm (cm -1 )S1AbsorptionEmissionSo
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