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What is a wave? The one-dimensional wave equation

What is a wave? The one-dimensional wave equation

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2/3/14Mathematical description ofEM <strong>wave</strong>s• Use of complex numbers to represent EM<strong>wave</strong>s• <strong>The</strong> complex refractive index– Scattering = real part– Absorption = imaginary part• Absorption and skin depth– Beer’s Law<strong>What</strong> <strong>is</strong> a <strong>wave</strong>?A <strong>wave</strong> <strong>is</strong> anything that moves.To d<strong>is</strong>place any function f(x) to theright, just change its argument fromx to x-a, where a <strong>is</strong> a positivenumber.If we let a = v t, where v <strong>is</strong> positiveand t <strong>is</strong> time, then the d<strong>is</strong>placementwill increase with time.So f(x - v t) represents a rightward,or forward, propagating <strong>wave</strong>.Similarly, f(x + v t) represents aleftward, or backward, propagating<strong>wave</strong>, where v <strong>is</strong> the velocity of the<strong>wave</strong>.For an EM <strong>wave</strong>, we could have E = f(x ± vt)f(x) f(x-2)f(x-1) f(x-3)0 1 2 3x1


2/3/14<strong>The</strong> <strong>one</strong>-<strong>dimensional</strong> <strong>wave</strong> <strong>equation</strong><strong>The</strong> <strong>one</strong>-<strong>dimensional</strong> <strong>wave</strong> <strong>equation</strong> for scalar (i.e., non-vector)functions, f:where v will be the velocity of the <strong>wave</strong>.<strong>The</strong> <strong>wave</strong> <strong>equation</strong> has the simple solution:where f (u) can be any twice-differentiable function.<strong>What</strong> about a harmonic <strong>wave</strong>?E = E 0cos k(x − ct)E 0 = <strong>wave</strong> amplitude (related to the energycarried by the <strong>wave</strong>).€k = 2π = angular <strong>wave</strong>numberλ = 2πν˜˜ ν(λ = <strong>wave</strong>length; = <strong>wave</strong>number = 1/λ)€Alternatively:E = E 0cos(kx − ωt)€Where ω = kc = 2πc/λ = 2πf = angularfrequency (f = frequency)€2


2/3/14<strong>What</strong> about a harmonic <strong>wave</strong>?E = E 0cos k(x − ct);φ = k(x − ct)<strong>The</strong> argument of the cosine function represents the phase of the <strong>wave</strong>,ϕ, or the fraction of a complete cycle of the <strong>wave</strong>.€In-phase <strong>wave</strong>sLine of equal phase = <strong>wave</strong>front = contours of maximum fieldOut-of-phase<strong>wave</strong>s<strong>The</strong> Phase VelocityHow fast <strong>is</strong> the <strong>wave</strong> traveling?Velocity <strong>is</strong> a reference d<strong>is</strong>tancedivided by a reference time.<strong>The</strong> phase velocity <strong>is</strong> the <strong>wave</strong>length / period: v = λ / τ Since f = 1/τ :v = λ fIn terms of k, k = 2π / λ, andthe angular frequency, ω = 2π / τ, th<strong>is</strong> <strong>is</strong>:v = ω / k3


2/3/14<strong>The</strong> Group VelocityTh<strong>is</strong> <strong>is</strong> the velocity at which the overall shape of the <strong>wave</strong>’s amplitudes,or the <strong>wave</strong> ‘envelope’, propagates. (= signal velocity)Here, phase velocity = group velocity (the medium <strong>is</strong> non-d<strong>is</strong>persive)D<strong>is</strong>persion: phase/group velocity depends on frequencyBlack dot moves at phase velocity. Red dot moves at group velocity.Th<strong>is</strong> <strong>is</strong> normal d<strong>is</strong>persion (refractive index decreases with increasing λ)4


2/3/14D<strong>is</strong>persion: phase/group velocity depends on frequencyBlack dot moves at group velocity. Red dot moves at phase velocity.Th<strong>is</strong> <strong>is</strong> anomalous d<strong>is</strong>persion (refractive index increases with increasing λ)Normal d<strong>is</strong>persion of v<strong>is</strong>ible lightShorter (blue) <strong>wave</strong>lengths refracted more than long (red) <strong>wave</strong>lengths.Refractive index of blue light > red light.5


2/3/14Complex numbersConsider a point,P = (x,y), on a 2DCartesian grid.Let the x-coordinate be the real partand the y-coordinate the imaginary partof a complex number.So, instead of using an ordered pair, (x,y), we write:P = x + i y= A cos(ϕ) + i A sin(ϕ)where i = √(-1)…or sometimes j = √(-1)Euler’s FormulaVoted the ‘Most Beautiful MathematicalFormula Ever’ in 1988Links the trigonometric functions and the complex exp<strong>one</strong>ntial functi<strong>one</strong>xp(iϕ) = cos(ϕ) + i sin(ϕ)so the point, P = A cos(ϕ) + i A sin(ϕ), can also be written:P = A exp(iϕ) = A e iφwhereA = Amplitudeϕ = Phase6


2/3/14Waves as rotating vectorsWaves using complex numbersE = E 0cos k(x − ct);φ = k(x − ct)<strong>The</strong> argument of the cosine function represents the phase of the <strong>wave</strong>,ϕ, or the fraction of a complete cycle of the <strong>wave</strong>.€Using complex numbers, we can write the harmonic <strong>wave</strong> <strong>equation</strong> as:E = E 0e ik(x −ct ) = E 0e i(kx−ωt )i.e., E = E 0 cos(ϕ) + i E 0 sin(ϕ), where the ‘real’ part of the expressionactually represents the <strong>wave</strong>.€We also need to specify the d<strong>is</strong>placement E at x = 0 and t = 0, i.e., the‘initial’ d<strong>is</strong>placement.7


2/3/14Amplitude and Absolute phaseE(x,t) = A cos[(k x – ω t ) – θ ]A = Amplitudeθ = Absolute phase (or initial, constant phase) at x = 0, t =0π kxWaves using complex numbersSo the electric field of an EM <strong>wave</strong> can be written:E(x,t) = E 0 cos(kx – ωt – θ)Since exp(iϕ) = cos(ϕ) + i sin(ϕ), E(x,t) can also be written:E(x,t) = Re { E 0 exp[i(kx – ωt – θ)] }Recall that the energy transferred by a <strong>wave</strong> (flux density) <strong>is</strong>proportional to the square of the amplitude, i.e., E 02 . Only theinteraction of the <strong>wave</strong> with matter can alter the energy of thepropagating <strong>wave</strong>.Remote sensing exploits th<strong>is</strong> modulation of energy.8


2/3/14Waves using complex amplitudesWe can let the amplitude be complex:Where the constant stuff <strong>is</strong> separated from the rapidly changing stuff.€E(x,t) = E 0exp[i(kx − ωt − θ)]E(x,t) = [ E 0exp(−iθ) ]exp[i(kx − ωt)]<strong>The</strong> resulting "complex amplitude”:<strong>is</strong> constant in th<strong>is</strong> case (as E 0 and θ are constant), which implies that themedium in which the <strong>wave</strong> <strong>is</strong> propagating <strong>is</strong> nonabsorbing.€[ E 0exp(−iθ) ]<strong>What</strong> happens to the <strong>wave</strong> amplitude upon interaction with matter?Vector fieldsHowever, light <strong>is</strong> a 3D vector field.A 3D vector field assigns a 3D vector (i.e., an arrow having bothdirection and length) to each point in 3D space.A light <strong>wave</strong> has both electric and magnetic 3D vector fields:And it can propagate in any direction, and point in any direction in space.9


2/3/14<strong>The</strong> 3D <strong>wave</strong> <strong>equation</strong> for the electric field and itssolutionA light <strong>wave</strong> can propagate in anydirection in space. So we must allowthe space derivative to be 3D:€€whose solution <strong>is</strong>: WhereAndE 0k = €E(x,y,z,t) = E 0exp(− k "⋅ x )exp([i( k '⋅ x − ωt)]<strong>is</strong> a constant, complex vectork '+ik "<strong>is</strong> a complex <strong>wave</strong> vector – the length of th<strong>is</strong>vector <strong>is</strong> inversely proportional to the <strong>wave</strong>length of the <strong>wave</strong>.Its magnitude <strong>is</strong> the angular <strong>wave</strong>number, k = 2π/λ.x = (x,y,z)<strong>is</strong> a position vector€€€<strong>The</strong> 3D <strong>wave</strong> <strong>equation</strong> for the electric field and itssolution€E(x,y,z,t) = E 0exp(− k "⋅ x )exp([i( k '⋅ x − ωt)]<strong>The</strong> vector <strong>is</strong> normal to planes of constant phase (and henceindicates the direction of propagation of <strong>wave</strong> crests) k "<strong>The</strong> vector <strong>is</strong> normal to planes of constant amplitude. Note thatthese are not necessarily parallel. €k '<strong>The</strong> amplitude of the <strong>wave</strong> at locationk "<strong>is</strong> now:So if <strong>is</strong> zero, then the medium <strong>is</strong> nonabsorbing, since theamplitude <strong>is</strong> constant . €€xE 0exp(−k "⋅x )10


2/3/14EM propagation in homogeneous materials<strong>The</strong> speed of an EM <strong>wave</strong> in free space <strong>is</strong> given by:ε 0 = permittivity of free space, µ 0 = magnetic permeability of free spaceTo describe EM propagation in other media,€two properties of the mediumare important, its electric permittivity ε and magnetic permeability µ.<strong>The</strong>se are also complex parameters.ε = ε 0 (1+ χ) + i σ/ω = complex permittivityσ = electric conductivityχ = electric susceptibility (to polarization under the influence of anexternal field)Note that ε and µ also depend on frequency (ω).c =1µ 0ε 0= ω kEM propagation in homogeneous materialsIn a non-vacuum, the <strong>wave</strong> must still sat<strong>is</strong>fy Maxwell’s Equations:v =1 µε = ω k€€We can now define the complex index of refraction, N, as the ratio ofthe <strong>wave</strong> velocity in free space to the velocity in the medium:N =µεµ 0ε 0= c v(n i= 0) or N = n r+ in iIf the imaginary part of N <strong>is</strong> zero, the material <strong>is</strong> nonabsorbing, and v <strong>is</strong>the phase velocity of the <strong>wave</strong> in the medium. For most physical media,N > 1 (i.e., the speed of light <strong>is</strong> reduced relative to a vacuum).NB. N <strong>is</strong> a property of a particular medium and also a function of ω11


2/3/14EM propagation in homogeneous materialsRelationships between the <strong>wave</strong> vector and the refractive index (theseare derived from Maxwell’s Equations):k ʹ′ = ω n rc= 2π λReal part of <strong>wave</strong> vector€€k ʹ′ ʹ′ = ω n ic= 2πνn icImaginary part of <strong>wave</strong> vector<strong>The</strong>se are the so-called ‘d<strong>is</strong>persion relations’ relating <strong>wave</strong>length,frequency, velocity and refractive index.Absorption of EM radiationRecall the expression for the flux density of an EM <strong>wave</strong> (Poyntingvector):F = 1 2 cε 0 E 2When absorption occurs, the flux density of the absorbed frequencies <strong>is</strong>reduced.€12


2/3/14Absorption of EM radiation<strong>The</strong> scalar amplitude of an EM <strong>wave</strong> at locationFrom the expression for the flux density we have:xF = F 0 [ exp(−k "⋅x )] 2 = F€ 0exp(−2k "⋅x )€<strong>is</strong>:E 0exp(−k "⋅x )€Absorption of EM radiationNow substitute the expression for :And we have:k ʹ′ ʹ′For a plane <strong>wave</strong> propagating in the x-direction.€F = F 0exp(− 4πνn ix)c€€k ʹ′ ʹ′ = ω n ic= 2πνn ic13


2/3/14Absorption coefficient and skin depthF = F 0exp(− 4πνn icx) = F 0e −β a xWhere β a <strong>is</strong> known as the absorption coefficient:<strong>The</strong> quantity 1/β a gives the d<strong>is</strong>tance required for the <strong>wave</strong>’s energy to be€attenuated to e -1 or ~37% of its original value, or the absorption/skindepth. It’s a function of frequency/<strong>wave</strong>length.€4πνn i= 4πn ic λAbsorption coefficient and skin depthWithin a certain material, an EM <strong>wave</strong> with λ = 1 µm <strong>is</strong> attenuated to10% of its original intensity after propagating 1 cm. Determine theimaginary part of the refractive index n i .14


2/3/14<strong>The</strong> Forced Oscillator:<strong>The</strong> relative phaseof the oscillatormotion withrespect to theinput forcedepends on thefrequencies.Let the oscillator’s resonantfrequency be ω 0 , and theforcing frequency be ω.We could think of theforcing function as a lightelectric field and theoscillator as a nucleus ofan atom in a molecule.Belowresonanceω > ω 0ForceOscillatorWeakvibration.In phase.Strongvibration.90° out ofphase.Weakvibration.180° outof phase.Courtesy Prof. Rick Trebino, Georgia Tech<strong>The</strong> relative phaseof an electroncloud’s motionwith respect toinput light dependson the frequency.Belowresonanceω > ω 0Weakvibration.In phase.Courtesy Prof. Rick Trebino, Georgia Tech15


2/3/14<strong>The</strong> relativephase ofemitted lightwith respect tothe input lightdepends on thefrequency.<strong>The</strong> emitted light <strong>is</strong>90° phase-shiftedwith respect to theatom’s motion.Belowresonanceω > ω 0Electric fieldat atomElectroncloudEmittedfieldWeakem<strong>is</strong>sion.90° out ofphase.Strongem<strong>is</strong>sion.180° outof phase.Weakem<strong>is</strong>sion.-90° outof phase.Courtesy Prof. Rick Trebino, Georgia TechRefractive index (n) – the d<strong>is</strong>persion <strong>equation</strong>n = 1+q 2e2ε 0m∑kq e = charge on an electronε 0 = electric constantm = mass of an electronN k € = number of charges (oscillators) of type k per unit volumeω = angular frequency of the EM radiationω k = resonant frequency of an electron bound in an atomγ = ‘damping coefficient’ for oscillator k (oscillation cannot be permanent)<strong>What</strong> <strong>is</strong> the refractive index of v<strong>is</strong>ible light in air?<strong>What</strong> happens as the frequency of EM radiation increases at constant ω k ?<strong>What</strong> happens if the resonant frequency <strong>is</strong> in the v<strong>is</strong>ible range?<strong>What</strong> happens if ω > ω k ? e.g., shine x-rays on glass, or radio <strong>wave</strong>s on freeelectrons.N kω k2− ω 2 + iγ kω16


2/3/14Refractive index (n) of water and icePenetration depth of water and ice(also called absorption depth or skin depth)17


2/3/14Refractive index and colorPaluweh volcanoAqua MODIS: Flores, Ind<strong>one</strong>sia; Feb 2, 2013 (250 meters)Color of suspended sedimentAqua MODIS: Flores, Ind<strong>one</strong>sia; Jan 23, 2013 (250 meters)18


2/3/14Complex refractive index of volcanic ashFrom: Krotkov et al. (1997), Ultraviolet optical model of volcanic clouds for remotesensing of ash and sulfur dioxide. J. Geophys. Res., 102 (D18), 21891-21904.19

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