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Fundamentals of Probability and Statistics for Engineers

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146 <strong>Fundamentals</strong> <strong>of</strong> <strong>Probability</strong> <strong>and</strong> <strong>Statistics</strong> <strong>for</strong> <strong>Engineers</strong>R 2x 2yx 1 + x 2 = yx 1yFigure 5. 20 Region R 2 :x 1 ‡ x 2 yConsiderable importance is attached to the results expressed by Equations(5.54) <strong>and</strong> (5.55) because sums <strong>of</strong> r<strong>and</strong>om variables occur frequently in practicalsituations. By way <strong>of</strong> recognizing this fact, Equation (5.55) is repeated nowas Theorem 5.3.Theorem 5. 3. Let Y ˆ X 1 ‡ X 2 ,<strong>and</strong> let X 1 <strong>and</strong> X 2 be independent <strong>and</strong> continuousr<strong>and</strong>om variables. Then the pdf <strong>of</strong> Y is the convolution <strong>of</strong> the pdfsassociated with X 1 <strong>and</strong> X 2 ;that is,f Y …y† ˆZ 1f X1…y1x 2 †f X2…x 2 †dx 2 ˆZ 1f X2…y x 1 †f X1…x 1 †dx 1 : …5:56†1Repeated applications <strong>of</strong> this <strong>for</strong>mula determine f Y (y) when Y is a sum <strong>of</strong>any number <strong>of</strong> independent r<strong>and</strong>om variables.Ex ample 5. 16. Problem: determine f Y (y) <strong>of</strong> Y ˆ X 1 ‡ X 2 when X 1 <strong>and</strong> X 2 areindependent <strong>and</strong> identically distributed according t<strong>of</strong> X1…x 1 †ˆ ae ax 1; <strong>for</strong> x 1 0;…5:57†0; elsewhere;<strong>and</strong> similarly <strong>for</strong> X 2 .Answer: Equation (5.56) in this case leads toZ yf Y …y† ˆa 2 e a…y x2† e ax 2dx 2 ; y 0; …5:58†0TLFeBOOK

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