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Fundamentals of Probability and Statistics for Engineers

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Linear Models <strong>and</strong> Linear Regression 341Table 11. 1 Percentage yield, y i , with process temperature, x i , <strong>for</strong> Example 11.1Ex ample 11. 1. Problem: it is expected that the average percentage yield, Y ,from a chemical process is linearly related to the process temperature, x, inC.Determine the least-square regression line <strong>for</strong> E fY g on the basis <strong>of</strong> 10 observationsgiven in Table 11.1.Answer: in view <strong>of</strong> Equations (11.7) <strong>and</strong> (11.8), we need the followingquantities:The substitution <strong>of</strong> these values into Equations (11.7) <strong>and</strong> (11.8) givesThe estimated regression line together with observed sample values is shownin Figure 11.2.It is noteworthy that regression relationships are valid only <strong>for</strong> the range<strong>of</strong> x values represented by the data. Thus, the estimated regression line inExample 11.1 holds only <strong>for</strong> temperatures between 45C<strong>and</strong>90C.Extrapolation<strong>of</strong> the result beyond this range can be misleading <strong>and</strong> is not valid in general.Another word <strong>of</strong> caution has to do with the basic linear assumption betweenE fY g <strong>and</strong> x. Linear regression analysis such as the one per<strong>for</strong>med in Example11.1 is based on the assumption that the true relationship between E fY g <strong>and</strong>x is linear. Indeed, if the underlying relationship is nonlinear or nonexistent,i1 2 3 4 5 6 7 8 9 10x (C) 45 50 55 60 65 70 75 80 85 90y 43 45 48 51 55 57 59 63 66 68X ṋi 1x ˆ 1 X nx i ˆ 1 …45 ‡ 50 ‡‡90† ˆ67:5;n 10iˆ1y ˆ 1 X ny i ˆ 1 …43 ‡ 45 ‡‡68† ˆ55:5;n 10iˆ1X niˆ1…x i x† 2 ˆ 2062:5;… x i x†…y i y† ˆ1182:5:^ ˆ 1182:52062:5 ˆ 0:57;^ ˆ 55:5 0:57…67:5† ˆ17:03:TLFeBOOK

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