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Fundamentals of Probability and Statistics for Engineers

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304 <strong>Fundamentals</strong> <strong>of</strong> <strong>Probability</strong> <strong>and</strong> <strong>Statistics</strong> <strong>for</strong> <strong>Engineers</strong><strong>and</strong>P… 2 > 752:3† ˆ0:95:9.3.2.4 Confidence Interval <strong>for</strong> a ProportionConsider now the construction <strong>of</strong> confidence intervals <strong>for</strong> p in the binomialdistributionIn the above, parameter p represents the proportion in a binomial experiment.Given a sample <strong>of</strong> size n from population X, we see from Example 9.10 that anunbiased <strong>and</strong> efficient estimator <strong>for</strong> p is X. For large n, r<strong>and</strong>om variable Xisapproximately normal with mean p <strong>and</strong> variance p1 p)/n.Defining p…1 p† 1=2U ˆ…X p† ; …9:146†nr<strong>and</strong>om variable U tends to N(0,1) as n becomes large. In terms <strong>of</strong> U, we havethe same situation as in Section 9.3.2.1 <strong>and</strong> Equation (9.129) givesThe substitution <strong>of</strong> Equation (9.146) into Equation (9.147) gives" #p…1 p† 1=2P u =2 < …X p† < u =2 ˆ 1 : …9:148†nIn order to determine confidence limits <strong>for</strong> p, we need to solve <strong>for</strong> p satisfyingthe equation p…1 p† 1=2jX pj u =2 ;nor, equivalentlyp X …k† ˆp k …1 p† 1 k ; k ˆ 0; 1:P… u =2 < U < u =2 †ˆ1 : …9:147†…X p† 2 u2 =2p…1 p†: …9:149†nTLFeBOOK

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