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Fundamentals of Probability and Statistics for Engineers

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Some Important Continuous Distributions 231the PDF <strong>of</strong> Z can be shown to have the <strong>for</strong>mF Z …z† ˆ1 expf exp‰…z u†Šg; 1 < z < 1 …7:105†where <strong>and</strong> u are again the two parameters <strong>of</strong> the distribution.It is seen that Type-I asymptotic distributions <strong>for</strong> maximum <strong>and</strong> minimumvalues are mirror images <strong>of</strong> each other. The mode <strong>of</strong> Z is u, <strong>and</strong> its mean,variance, <strong>and</strong> skewness coefficients are, respectively, 9m Z ˆ u >= 2 Z ˆ 2…7:106†6 2>; 1 ' 1:1396For probability calculations, values <strong>for</strong> probability distribution functionsF Y (y) <strong>and</strong> F Z (z) over various ranges <strong>of</strong> y <strong>and</strong> z are available in, <strong>for</strong> example,Micros<strong>of</strong>t Excel 2000 (see Appendix B).Ex ample 7. 9. Problem: the maximum daily gasoline dem<strong>and</strong> Y during themonth <strong>of</strong> May at a given locality follows the Type-I asymptotic maximumvaluedistribution, with m Y ˆ 2<strong>and</strong> Y ˆ 1, measured in thous<strong>and</strong>s <strong>of</strong> gallons.Determine (a) the probability that the dem<strong>and</strong> will exceed 4000 gallons inany day during the month <strong>of</strong> May, <strong>and</strong> (b) the daily supply level that <strong>for</strong> 95%<strong>of</strong> the time will not be exceeded by dem<strong>and</strong> in any given day.Answer: it follows from Equations (7.102) <strong>and</strong> (7.103) that parameters <strong>and</strong>u are determined fromFor part (a), the solution is ˆ p ˆ p ˆ 1:282;6 Y 60:577u ˆ m Y ˆ 2 0:5771:282 ˆ 1:55:P…Y > 4† ˆ1 F Y …4†ˆ 1 expf exp‰ 1:282…4 1:55†Šgˆ 1 0:958 ˆ 0:042:For part (b), we need to determine y such thatF Y …y† ˆP…Y y† ˆ0:95;TLFeBOOK

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