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Fundamentals of Probability and Statistics for Engineers

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Some Important Continuous Distributions 203<strong>and</strong> 11.2cm, what proportion <strong>of</strong> the manufactured parts will be rejected onaverage?Answer: If X is used to denote the part length in centimeters, it is reasonableto assume that it is distributed according to N(11, 0.04). Thus, on average, theproportion <strong>of</strong> acceptable parts is P10:6 < X 11:2). From Equation (7.25),<strong>and</strong> using Table A.3, we have10:6 11P…10:6 < X 11:2† ˆP < U 0:211:2 110:2ˆ P… 2 < U 1† ˆF U …1† ‰1 F U …2†Šˆ 0:8413 …1 0:9772† ˆ0:8185:The desired answer is then 1 0:8185, which gives 0.1815.The use <strong>of</strong> the normal distribution in Example 7.3 raises an immediateconcern. Normal r<strong>and</strong>om variables assume values in positive <strong>and</strong> negativeranges, whereas the length <strong>of</strong> a machine part as well as many other physicalquantities cannot take negative values. However, from a modeling point <strong>of</strong>view, it is a commonly accepted practice that normal r<strong>and</strong>om variables are validrepresentations <strong>for</strong> nonnegative quantities in as much as probability P(X < 0)is sufficiently small. In Example 7.3, <strong>for</strong> example, this probability isP…X < 0† ˆP U < 11 ˆ P…U < 55† 00:2Ex ample 7. 4. Let us compute Pm k

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