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2013 Conference Proceedings - University of Nevada, Las Vegas

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APPENDIXTable 5Description <strong>of</strong> Combinatorics Problems in Focus Group for participants to solveName Description Type & SolutionSequenceAn exam contains 15 multiple-choice questions, each with 4 choices. HowMC Exams1many possible ways <strong>of</strong> answering these 15 questions are there?Plane RoutesSupremeCourtDecisionsSummedDigitsGift CardsSkittlesThe M/FCommitteesProblemNetflixMC Exams24-letter wordsMarblesPizzaToppingsA plane starts in New York City and will travel to 7 different cities before itreturns. How many different ways can the plane do this?In how many different ways can the nine members <strong>of</strong> the Supreme Courtreach a six-to-three decision?How many numbers between 1 and 10,000 have the sum <strong>of</strong> their digitsequal to 9?How many ways can you distribute a $1, $2, $5, $10, and $20 gift card to 8friends?16 skittles go into the small Halloween skittle bags. There are 5 colors tochoose from in each bag – Red, Green, Yellow, Orange, and Purple. Howmany different possible bags <strong>of</strong> skittle are there?There are 7 women and 4 men in a club. How many different 4-personcommittees have at least two women?You have 24 different movies on your Netflix account. In how manydifferent ways could you order them?An exam contains 15 multiple-choice questions, each with 4 choices. Inhow many <strong>of</strong> the possible ways to answer the exam are at least 10 correct?Suppose you make a 4-letter “word” (nonsense words count) from theletters A, B, C, D, and E, where you can repeat letters. How many different“words” are possible?How many ways are there to distribute 25 indistinguishable marbles into 7different containers?How many ways are there to make a pizza with 2 toppings, if the choicesare pepperoni, olives, sausage, ham, mushrooms, and anchovies (doubletoppings allowed)?4 15Arrangement7!Subsetæ 9öçè 6 ÷ ø= æ 9 öçè 3 ÷øMultisubsetææ4ööçèçè 9÷ø÷ ø= æ 9 + 3 öçè 3 ÷øSequence8 5Multisubsetææ5 ööçèçè16÷ø÷ ø= æ 16 + 4 öçè 4 ÷øSubsetæ 7öæ 4öçè 2÷øçè 2 ÷ ø+ æ 7 ö æ 4öçè 3 ÷øçè1÷ ø+ æ 7 öçè 4 ÷øArrangement24!Subset15åk=10æ15öçè k ÷øSequence5 4Multisubsetææ7 ö öçèçè 25÷ø ÷ø= æ 25 + 6 öçè 6 ÷øMultisubsetææ6ööçèçè 2÷ø ÷ø= æ 2 + 5 öçè 5 ÷ø<strong>Proceedings</strong> <strong>of</strong> the 40 th Annual Meeting <strong>of</strong> the Research Council on Mathematics Learning <strong>2013</strong> 154

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