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Setup of a Drift Tube Muon Tracker and Calibration of Muon ...

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N [a.u]Reconstructed <strong>Drift</strong> Circles1000h1Entries 34970Mean 9.153RMS 5.1880060040020000 2 4 6 8 10 12 14 16 18 20r [mm]Figure 3.17: Distribution <strong>of</strong> radii r from reconstructed drift distances. The radii aredistributed homogeneously except for the region around the center. This is due to thelarge uncertainties <strong>of</strong> the TDC count to distance relation in this region.small peak in the second bin <strong>of</strong> the distribution. However, the overall performanceis satisfactory.3.8.4 Spatial <strong>and</strong> Angular ResolutionBoth the spatial <strong>and</strong> angular resolutions can be determined from the reconstructeddata. Fig. 3.18 shows the distribution <strong>of</strong> residuals from all fitted tracks. The RMSvalue gives a measure for the lateral resolution σ r <strong>of</strong> the detector. It has been foundto be σ r = 270ñm. The angular resolution can be determined by comparing tracksreconstructed in each single module. For a perfect reconstruction, the fitted anglesα should be identical for all modules. However, comparing the angles for tracks<strong>of</strong> the same event reconstructed in two modules <strong>of</strong> the same 2D plane separatelyshows slight differences. The distribution <strong>of</strong> ∆α for real data is shown in Fig. 3.19.A sharp peak around zero is observed. To obtain a measure for the resolution, aVoigtian was fitted to the distribution. A Voigtian is a convolution <strong>of</strong> a Gaussian<strong>and</strong> a Breit-Wigner distribution. The σ <strong>of</strong> the fit is then obtained from the FWHMdivided by 2.35. For the CMT, a value <strong>of</strong> σ fit = 6.98 mrad has been found. Since twomodules are taken into account, the error <strong>of</strong> the reconstructed angle is taken intoaccount twice. It is therefore overestimated in the direct comparison. This effectcan be compensated for, by dividing σ by √ 2. Consequently the angular resolutionσ α is given by:σ α = σ fit√2= 4.65mrad.49

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