18.04.2016 Views

isolated current voltage transducers

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Hall Effect Technologies<br />

specified measuring range; a check on the transducer<br />

secondary side is required to see if this transient<br />

measurement is nevertheless possible<br />

For the latter point, as discussed in § 3.2.10 – example 2,<br />

it is sometimes possible to measure a <strong>current</strong> beyond that<br />

specified in the transducer datasheet, more precisely<br />

when the measurement resistor is not exceeding a<br />

maximum R Mmax<br />

value. In this example, we have:<br />

• the conversion ratio of the transducer is 10000 / 2000,<br />

giving a secondary <strong>current</strong> of I S<br />

= 5 • 21.8 = 109 mA<br />

• the <strong>voltage</strong> available at the amplifier output is (Fig. 12)<br />

V A<br />

= (R S<br />

+ R Mmax<br />

) • I S<br />

= (60 + 150)Ω • 50 mA = 10.5 V<br />

• the maximum measurement value is<br />

R Mmax<br />

= (V A<br />

/ I S<br />

) -R S<br />

= (10.5 / 0.109) – 60 = 36.3Ω<br />

In conclusion, measuring a 500 V transient is possible if a<br />

measurement resistance lower than 36.1 Ω is used.<br />

c) Measurement accuracy: influence of the serial resistance<br />

R 1<br />

and primary resistance R P<br />

The measurement principle discussed in § 3.4.1 is based<br />

on the measurement of a <strong>current</strong> I mes<br />

(Fig. 21) proportional<br />

to the <strong>voltage</strong> to be measured. The two main factors<br />

affecting the measurement accuracy are:<br />

• The accuracy of the measurement of the collected<br />

<strong>current</strong> I mes<br />

• Unexpected changes of the ratio between the collected<br />

I mes<br />

<strong>current</strong> and the <strong>voltage</strong> to be measured.<br />

Thus, changes of the resistances R 1<br />

and R P<br />

will affect the<br />

measurement accuracy, since it will change the value of<br />

the I mes<br />

<strong>current</strong>.<br />

The example below calculates the impact on accuracy of<br />

a change in resistances, due to both resistance tolerances<br />

and temperature effects. A LV 100 <strong>voltage</strong> transducer is<br />

considered, with a +20°C to +70°C worst case working<br />

temperatures.<br />

Reference case<br />

The reference value of the <strong>current</strong> to be measured, I mes<br />

, is<br />

defined as the value obtained at +70°C when both<br />

resistors R 1<br />

and R P<br />

have their nominal value. These<br />

values are R 1<br />

= 21.0 kΩ (as calculated in point a), at<br />

+70°C) and R P<br />

= 1.9 kΩ (data-sheet, measured value).<br />

The collected I mes<br />

<strong>current</strong> is then equal to 230 V / (21 +<br />

1.9) kΩ = 10 mA<br />

Maximum error<br />

The value of the resistances are smaller at +20 °C when<br />

compared to +70 °C. The worst case shall additionally<br />

consider the tolerance on the resistances' value when at<br />

their minimum.<br />

For the resistance R 1<br />

, typical values for the temperature<br />

drift and tolerance are 50ppm/°C and ± 0.5% respectively.<br />

The minimum value becomes:<br />

R 1<br />

= 21’000 • (1 - 50 • 50 • 10 -6 ) • (1 – 0.005) = 20’942 Ω<br />

The primary resistance R P<br />

is made of copper and exhibits<br />

a resistance change with temperature as follows:<br />

R PF<br />

= R P20<br />

(1 + α • ∆T) where<br />

R PF<br />

: resistance at Final temperature (e.g. +70 °C)<br />

R P20<br />

: resistance at +20 °C<br />

α : copper temperature coefficient = 0.004 K -1<br />

∆T : change in temperature (Final – 20 °C), positive<br />

when above +20 °C<br />

Note that the temperature of the R P<br />

copper is likely to be<br />

higher than the maximum ambient temperature due to<br />

internal transducer heatings.<br />

In our case:<br />

R P20<br />

= 1’900 / (1 + 0.004 • 50) = 1’538 Ω<br />

Collected <strong>current</strong> become equal to I mes<br />

= 230 V / (20’942 +<br />

1’538) = 10.21 mA, corresponding to a +2.1 % error<br />

compared to the reference value.<br />

The measurement accuracy of the I mes<br />

<strong>current</strong> has still to<br />

be added to this 2.1 % error.<br />

d) What is the accuracy of the transducer, converting the<br />

primary <strong>current</strong> into an <strong>isolated</strong> output signal ?<br />

In this case, we assume that the resistor R 1<br />

has been<br />

selected in order to have a 10 mA primary <strong>current</strong> I PN<br />

.<br />

According to the LV 100 datasheet, the accuracy of the<br />

<strong>current</strong> measurement at 25 °C is ±0.7 % of I PN<br />

. The<br />

thermal drift of the offset <strong>current</strong> is ±0.3 mA max. With a<br />

conversion ratio of 10000:2000, the input <strong>current</strong> of<br />

10 mA generates an output <strong>current</strong> of 50 mA. The values<br />

of the errors are:<br />

Accuracy at 25 °C ±0.7 % of I PN<br />

±0.7 %<br />

Temperature offset drift ±0.3 mA/50 mA ±0.6 %<br />

Maximum error of the <strong>current</strong> measurement: ±1.3 %<br />

e) What is the total measurement error?<br />

The effects listed in c) and d) above provide the total<br />

measurement error of the output <strong>current</strong> of the transducer.<br />

Typical applications include a measuring resistance, R M<br />

,<br />

to convert this output into a <strong>voltage</strong> for measurement.<br />

Assuming typical parameters for R M<br />

, we have an intial<br />

tolerance of ±0.5 % and a 50 ppm/K temperature drift,<br />

giving a 0.225 % variation for a 20 °C to 70 °C<br />

temperature range. The total R M<br />

error becomes 0.5 +<br />

0.225 = 0.725 %.<br />

For the LV 100 transducer, the total measurement error at<br />

the 230 V nominal, considering a temperature range of<br />

20 to 70°C, is the combination of the effects in c) and d)<br />

and R M<br />

above:<br />

total measurement error =<br />

2.1 % + 1.30 % + 0.725 % = 4.125 %<br />

23

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!