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7. Predict the product for the following case,<br />
Cl Cl<br />
conc.<br />
11.<br />
HSO<br />
Br 4<br />
2<br />
?<br />
Naphthalene<br />
60°C-70°C<br />
160°C<br />
NO 2<br />
Br Br<br />
Cl <br />
SO 3 H<br />
(a)<br />
(b)<br />
(a) A =<br />
; B =<br />
Cl <br />
(c)<br />
<br />
(d) None of these<br />
(b)<br />
SO 3 H<br />
8.<br />
(c) Both will be<br />
.<br />
CH 3<br />
CH 3<br />
(d) Both will be<br />
(a)<br />
(b)<br />
SOLUTIONS<br />
(c) + CH 4 (d) None of these<br />
1. (d): Isopentane is<br />
9.<br />
This species is<br />
(W) ⇒<br />
(a) aromatic (b) non-aromatic<br />
CH 2<br />
CH CH 2<br />
CH 3<br />
(c) anti-aromatic (d) heterocyclic.<br />
Cl CH 3<br />
10.<br />
HNO 3<br />
/HSO 1-chloro-2-methylbutane<br />
2 4<br />
0°C<br />
(a) ON 2<br />
(b) ON 2<br />
NO 2<br />
(c) NO 2<br />
2<br />
A<br />
(major)<br />
B (major)<br />
SO H 3<br />
.<br />
SO H 3<br />
Substitution at 1°(a) or 1°(b) carbon will give the<br />
same product. It will be :<br />
Substitution at 1°(c) carbon will give a different<br />
product.<br />
(X) ⇒<br />
Substitution at 2° carbon will give different product.<br />
(Y) ⇒<br />
(d)<br />
Substitution at 3° carbon will give different<br />
product.<br />
66 CHEMISTRY TODAY | APRIL ‘17
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