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(a) HN 2 SO 3 H<br />

(b) (NH 2 ) 2 CO<br />

(c) C 6 H 5 SO 3 H<br />

(d) (NH 4 ) 2 SO 4<br />

PARAGRAPH 2<br />

In stereoisomerism, the isomers differ only in the<br />

spatial arrangement of groups about the central metal<br />

atom. It is of two types : (i) Geometrical isomerism, this<br />

isomerism arises in heteroleptic <strong>com</strong>plexes due to the<br />

difference in geometrical <strong>com</strong>plexes and geometrical<br />

arrangement of the ligands around the central atom.<br />

(ii) Optical isomerism, this isomerism is shown by chiral<br />

molecules, i.e., the molecules which do not have plane<br />

of symmetry.<br />

35. The number of isomers exhibited by [Cr(NH 3 ) 3 Cl 3 ] is<br />

(a) 2 (b) 3 (c) 4 (d) 5<br />

36. Which of the following will exhibit optical<br />

isomerism?<br />

(a) [Cr(en)(H 2 O) 4 ] 3+<br />

(b) [Cr(en) 3 ] 3+<br />

(c) trans-[Cr(en)Cl 2 (NH 3 ) 2 ] +<br />

(d) trans-[Cr(en) 2 Cl 2 ] +<br />

MATHEMATICS<br />

SECTION 1 (Maximum Marks : 18)<br />

• This section contains SI questions.<br />

• Each question has FOUR options (a), (b), (c) and (d). ONLY ONE<br />

of these four options is correct.<br />

• For each question, darken the bubble corresponding to the<br />

correct option in the ORS.<br />

• For each question, marks will be awarded in one of the following<br />

categories :<br />

Full Marks : +3 If only the bubble corresponding to the correct<br />

option is darkened.<br />

Zero Marks : 0 If none of the bubbles is darkened.<br />

Negative Marks : –1 In all other cases.<br />

39. If the angle between the curves y = 2 x and y = 3 x is<br />

α, then the value of tanα is equal to<br />

log( 3/ 2)<br />

6<br />

(a)<br />

(b)<br />

1+<br />

(log 2)(log 3)<br />

7<br />

1<br />

log( 6)<br />

(c)<br />

(d)<br />

7<br />

1+<br />

(log 2)(log 3)<br />

40. The solution of the differential equation<br />

ysin(x/y)dx = (xsin(x/y) – y)dy satisfying y(/4) = 1<br />

is<br />

x<br />

(a) cos = loge<br />

y + 1 y<br />

2 (b) x<br />

sin = loge<br />

y + 1 y<br />

2<br />

x<br />

(c) sin = loge<br />

x − 1 y<br />

2<br />

x<br />

(d) cos =−loge<br />

x − 1 y<br />

2<br />

41. Let a, b be two distinct roots of acosq + bsinq = c,<br />

where a, b and c are three real constants and q [0, 2].<br />

Then a+ bis also a root of the same equation, if<br />

(a) a + b = c<br />

(b) b + c = a<br />

(c) c + a = b<br />

(d) c = a<br />

42. If x 1 , x 2 , ..., x 18 are observations such that<br />

18<br />

j=<br />

1<br />

18<br />

∑( x j − 8)<br />

= 9 and ∑( x j − 8) 2 = 45,<br />

then the<br />

j=<br />

1<br />

standard deviation of these observations is<br />

81<br />

(a) (b) 5 (c) 5 (d) 3/2<br />

34<br />

SECTION 2 (Maximum Marks : 32)<br />

• This section contains EIGHT questions.<br />

• Each question has FOUR options (a), (b), (c) and (d). ONE OR<br />

MORE THAN ONE of these four option(s) is(are) correct.<br />

• For each question, darken the bubble(s) corresponding to all the<br />

correct option(s) in the ORS.<br />

• For each question, marks will be awarded in one of the following<br />

categories :<br />

Full Marks : +4 If only the bubble(s) corresponding to all the<br />

⎛1<br />

− x ⎞<br />

correct option(s) is(are) darkened.<br />

⎜ ⎟<br />

⎛ 1 + x ⎞⎝<br />

1 − x ⎠<br />

Partial Marks : +1 For darkening a bubble corresponding<br />

37. lim<br />

to each correct option, provided NO incorrect option is<br />

x<br />

⎜<br />

→ ⎝ + x<br />

⎟<br />

1 2 ⎠<br />

darkened.<br />

(a) is 1<br />

(b) does not exist<br />

Zero Marks : 0 If none of the bubbles is darkened.<br />

Negative Marks : –2 In all other cases.<br />

• For example, if (a), (c) and (d) are all the correct options for<br />

2<br />

(c) is<br />

(d) is ln 2<br />

a question, darkening all these three will result in +4 marks;<br />

3<br />

darkening only (a) and (d) will result in +2 marks; and darkening<br />

(a) and (b) will result in –2 marks, as a wrong option is also<br />

1<br />

dx<br />

darkened.<br />

38. If I = ∫ , then<br />

1<br />

π/ 2<br />

0<br />

+ x<br />

43. Let PQR be a triangle. Let <br />

a= QRb , = RP and c = PQ.<br />

<br />

(a) log e 2 < I < π/4 (b) log e 2 > I a= QRb , = RP and c = PQ.<br />

If | <br />

a| = 12,| b|<br />

= 4 3 and <br />

b⋅<br />

c =24, then<br />

(c) I = π/4 (d) I = log e 2<br />

which of the following is (are) true?<br />

76 CHEMISTRY TODAY | APRIL ‘17

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