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7. (d) : Cyclopropane is under severe strain. Therefore,<br />
it is always ready to undergo ring opening<br />
reactions.<br />
∴ Option (d) is correct.<br />
Remember, when a carbanionic centre attached<br />
with two chlorine atoms, substitution reaction<br />
takes place. Also remember, in presence of sunlight<br />
ring opening and substitution takes place via free<br />
radical path.<br />
8. (a) : Under vigorous conditions, Ni/H 2<br />
will destroy<br />
the double bonds of benzene.<br />
∴ Option (a) will be the correct option.<br />
9. (b): System is not conjugated. So, it is nonaromatic.<br />
∴ Option (b) is correct.<br />
10. (a) : Nitration will take place at o- or p-positions<br />
of the aromatic ring if +I-effect group is attached<br />
to the benzene ring. Hence, option (a) is correct.<br />
Lower temperature prevents polynitration.<br />
11. (a) : While electrophilic substitution reaction takes<br />
place in naphthalene there are two positions where<br />
it can take place, α and β.<br />
H E<br />
H<br />
+<br />
III<br />
E +<br />
-attack<br />
60°C–70°C<br />
E<br />
I<br />
H<br />
II<br />
+<br />
E<br />
+<br />
+<br />
E<br />
E + H<br />
-attack<br />
160°C<br />
VI<br />
E<br />
E<br />
H<br />
H<br />
+<br />
+<br />
VIII<br />
VII<br />
E<br />
+<br />
E<br />
H<br />
H<br />
+<br />
IX<br />
X<br />
So, intermediates for α-attack are more stable than<br />
that for β-attack. So, α-product must be kinetically<br />
controlled product and at low temperature this<br />
be<strong>com</strong>es irreversible in nature and the exclusive<br />
product. α-product is thermodynamically less stable<br />
than β-product due to steric reason.<br />
No steric<br />
interaction<br />
H<br />
-product<br />
SO H 3<br />
Steric<br />
interaction<br />
H<br />
-product<br />
SO H 3<br />
This is why at higher temperature reaction occurs<br />
to give thermodynamically more stable β-product.<br />
At higher temperature reaction is also reversible in<br />
nature. At higher temperature the readily formed<br />
α-product desulfonates and gives β-product.<br />
SO 3<br />
H<br />
-product<br />
H +<br />
H 2<br />
SO 4<br />
H + H 2<br />
SO 4<br />
SO 3 H<br />
+<br />
H<br />
E<br />
H<br />
E<br />
-product<br />
+<br />
IV<br />
V<br />
Now, understand a very simple thing, for α-attack<br />
there are two structures whereas for β-attack there<br />
is only one structure which is aromatic. For α-attack<br />
the aromatic structures are I and II and for β-attack<br />
the aromatic structure is VI.<br />
P.E<br />
E act (I)<br />
E act<br />
(II)<br />
-product<br />
Naphthalene +<br />
conc. H 2<br />
SO -product<br />
4<br />
Reaction co-ordinate<br />
-zone product -zone product<br />
<br />
68 CHEMISTRY TODAY | APRIL ‘17