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Use the space provided to write out the steps you take to solve different types of problems.<br />
Use any additional space for notes. These 2 pages should be full when you turn in your notebook.<br />
Steps to solve problems<br />
Mole to Mole:<br />
In these mole to mole ratios, you will start off with what the problem gives you<br />
(what is given). In this example, the problem gives you 6 moles of H2 and asks<br />
you to convert it into moles of O2. So like I said, you put 6 mol H2 in the top left<br />
space. After that you have to convert it into moles of H2 again, but this time it's<br />
the specified amount in the equation. So 6 mol H2--> 2 mol H2. But you're not<br />
done! On top of the 2 mol H2, you need to match it with the specified moles of<br />
the product in the problem, in this example it is 1 mole of O2. So you multiply<br />
the top and bottom and then divide the top by the bottom and you get your<br />
answer! Here it is 3 mol O2.<br />
Mole to Mass: 2C + 2H2O --> CH4 + CO2<br />
If you have 1 mol of CH4, how many grams of C would you have?<br />
1 mol CH4 2 mol C 2 mol = 2 g C<br />
1 mol CH4 1 mol<br />
For Mole to mass ratios, it is simple. You begin with the given amount in the<br />
problem, in this case it is 1mol of CH4. At this point you convert the mols of<br />
CH4 to mols of C using the reaction. In this case, 2 mols of C=1 mol CH4. Then<br />
you just multiply and divide the top and bottom and here you come up<br />
with 2 g of Carbon.<br />
Mass to Mass: 20 g of propane combust, how many g of water are<br />
produced?<br />
C 3 H 8 + 5O 2 --> 4H 2 O + 3CO 2<br />
20 G C3H8 1 mol Ch3H8 4 mol H2O 18 g H2O 1440 = 33 g H2O<br />
44 g C3H8 1 mol C3H8 1 mol H2O 44<br />
For this equation I explain it below: (in green)