25.05.2017 Views

Qrtr 4 final

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

each. With this in tow, a reactant takes less time to build up enough energy to convert. It comes to<br />

the same end as if it was just the reactant without the catalysts, since catalysts don’t react with the<br />

substances. It just happens faster.<br />

8 Which reaction diagram shows the effect of using the appropriate catalyst in a chemical reaction?<br />

A<br />

C<br />

B<br />

D<br />

Similar to question 1 , Catalysts allow a reaction to proceed along a lower energy path. The<br />

graph is actually fairly similar to that of question 1 so i’ll explain it the same way. Before the catalyst,<br />

the reaction proceeds like normal with a normal activation energy. However, with the catalyst, the<br />

activation energy is brought way down. That’s why you can see in the graph where “After Catalyst” is<br />

pointing, the point of reaction is at a lower energy than the original reaction.<br />

9 H​ 2​<br />

O​ 2,​<br />

hydrogen peroxide, naturally breaks down into H​ 2​<br />

O and O​ 2​<br />

over time. MnO​ 2​<br />

, manganese<br />

dioxide, can be used to lower the energy of activation needed for this reaction to take place and, thus,<br />

increase the rate of reaction. What type of substance is MnO​ 2​<br />

?<br />

A a catalyst<br />

B an enhancer<br />

C an inhibitor<br />

D a reactant<br />

MnO2 would be a catalyst because it facilitates the rate of reaction in this situation. It lowers<br />

the activation rate for the reaction and so it would make the whole process faster. When MnO2 acts<br />

as a catalyst and lowers the activation energy, it quickens the rate of reaction rate because the<br />

reactants no longer have to reach the same high (higher) level of energy that they used to. Once<br />

MnO2 lowers the activation energy, the reactants need less time to build up the energy to form the<br />

reaction and in the end, it takes less time.<br />

10 When a reaction is at equilibrium and more reactant is added, which of the following changes is<br />

the immediate result?<br />

A The reverse reaction rate remains the same.<br />

B The forward reaction rate increases​.<br />

C The reverse reaction rate decreases.<br />

D The forward reaction rate remains the same.<br />

The forward reaction rate of the reaction would increase when more reactant is added. This is<br />

because equilibrium is the state where the same amount of reactant is being converted as there is<br />

product being decomposed. The rate of the reactant reacting slows down over time because less<br />

reactant is available to react (that was difficult to word). If you added more reactant to the system, the<br />

forward reaction rate (ie the original reaction) would increase because more “”stuff”” is available to<br />

react. If it runs out, it will slow down, but adding reactant moves the reaction along.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!