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each. With this in tow, a reactant takes less time to build up enough energy to convert. It comes to<br />
the same end as if it was just the reactant without the catalysts, since catalysts don’t react with the<br />
substances. It just happens faster.<br />
8 Which reaction diagram shows the effect of using the appropriate catalyst in a chemical reaction?<br />
A<br />
C<br />
B<br />
D<br />
Similar to question 1 , Catalysts allow a reaction to proceed along a lower energy path. The<br />
graph is actually fairly similar to that of question 1 so i’ll explain it the same way. Before the catalyst,<br />
the reaction proceeds like normal with a normal activation energy. However, with the catalyst, the<br />
activation energy is brought way down. That’s why you can see in the graph where “After Catalyst” is<br />
pointing, the point of reaction is at a lower energy than the original reaction.<br />
9 H 2<br />
O 2,<br />
hydrogen peroxide, naturally breaks down into H 2<br />
O and O 2<br />
over time. MnO 2<br />
, manganese<br />
dioxide, can be used to lower the energy of activation needed for this reaction to take place and, thus,<br />
increase the rate of reaction. What type of substance is MnO 2<br />
?<br />
A a catalyst<br />
B an enhancer<br />
C an inhibitor<br />
D a reactant<br />
MnO2 would be a catalyst because it facilitates the rate of reaction in this situation. It lowers<br />
the activation rate for the reaction and so it would make the whole process faster. When MnO2 acts<br />
as a catalyst and lowers the activation energy, it quickens the rate of reaction rate because the<br />
reactants no longer have to reach the same high (higher) level of energy that they used to. Once<br />
MnO2 lowers the activation energy, the reactants need less time to build up the energy to form the<br />
reaction and in the end, it takes less time.<br />
10 When a reaction is at equilibrium and more reactant is added, which of the following changes is<br />
the immediate result?<br />
A The reverse reaction rate remains the same.<br />
B The forward reaction rate increases.<br />
C The reverse reaction rate decreases.<br />
D The forward reaction rate remains the same.<br />
The forward reaction rate of the reaction would increase when more reactant is added. This is<br />
because equilibrium is the state where the same amount of reactant is being converted as there is<br />
product being decomposed. The rate of the reactant reacting slows down over time because less<br />
reactant is available to react (that was difficult to word). If you added more reactant to the system, the<br />
forward reaction rate (ie the original reaction) would increase because more “”stuff”” is available to<br />
react. If it runs out, it will slow down, but adding reactant moves the reaction along.