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Bate, Mueller, and White - Fundamentals of Astrodynamics ... - UL FGG

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14 TWO·BODY ORBITAL MECHANICS Ch. 1<br />

some planet or the sun, the mass <strong>of</strong> the orbiting body, m, will be much<br />

less than that <strong>of</strong> the central body, M. Hence we see that<br />

G(M+m) :::: :: GM.<br />

It is convenient to define a parameter, Il (mu), called the gravitational<br />

parameter as<br />

Il == GM.<br />

Then equation 1.3·3 becomes<br />

I t"+ * r = 0·1<br />

(1.3·4)<br />

Equation (1.3 4) is the two·body equation <strong>of</strong> motion that we will use<br />

for the remainder <strong>of</strong> the text. Remember that the results obtained from<br />

equation (1.34) will be only as accurate as the assumptions (1) <strong>and</strong> (2)<br />

<strong>and</strong> the assumption that M m. If m is not much less than M, then<br />

G (M + m ) must be used in place <strong>of</strong> Il (so defined by some authors). Il<br />

will have a different value for each major attracting body. Values for<br />

the earth <strong>and</strong> sun are listed in the appendix <strong>and</strong> values for other planets<br />

are included in Chapter 8.<br />

1.4 CONSTANTS OF THE MOTION<br />

Before attempting to solve the equation <strong>of</strong> motion to obtain the<br />

trajectory <strong>of</strong> a satellite we shall derive some useful information about<br />

the nature <strong>of</strong> orbital motion. If you think about the model we have<br />

created, namely a small mass moving in a gravitational field whose force<br />

is always directed toward the center <strong>of</strong> a larger mass, you would<br />

probably arrive intuitively at the conclusions we will shortly confirm by<br />

rigorous mathematical pro<strong>of</strong>s. From your previous knowledge <strong>of</strong><br />

physics <strong>and</strong> mechanics you know that a gravitational field is<br />

"conservative." That is, an object moving under the influence <strong>of</strong> gravity<br />

alone does not lose or gain mechanical energy but only exchanges one<br />

form <strong>of</strong> energy, "kinetic," for another form called "potential energy."<br />

You also know that it takes a tangential component <strong>of</strong> force to change<br />

the angular momentum <strong>of</strong> a system in rotational motion about some<br />

center <strong>of</strong> rotation. Since the gravitational force is always directed<br />

radially toward the center <strong>of</strong> the large mass we would expect that the<br />

angular momentum <strong>of</strong> the satellite about the center <strong>of</strong> our reference

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