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University Physics I - Classical Mechanics, 2019

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8.5. IN SUMMARY 175<br />

As we shall see later, the product Rα is also a useful quantity. It is not, however, equal to the magnitude<br />

of the acceleration vector, but only one of its two components, the tangential acceleration:<br />

a t = Rα (8.37)<br />

The sign convention here is that a positive a t represents a vector that is tangent to the circle and<br />

points in the direction of increasing θ (that is, counterclockwise); the full acceleration vector is<br />

equal to the sum of this vector and the centripetal acceleration vector, introduced in the previous<br />

subsection, which always points towards the center of the circle and has magnitude<br />

a c = v2<br />

R = Rω2 (8.38)<br />

(making use of Eqs. (8.29)and(8.36)). These results will be formally established in the next chapter,<br />

after we introduce the vector product, although you could also verify them right now—if you are<br />

familiar enough with derivatives at this point—by using the chain rule to take the derivatives with<br />

respect to time of the components of the position vector, as given in Eq. (8.30) (withθ = θ(t), an<br />

arbitrary function of time).<br />

The main thing to remember about the radial and tangential components of the acceleration is that<br />

the radial component (the centripetal acceleration) is always there for circular motion, whether the<br />

angular velocity is constant or not, whereas the tangential acceleration is only nonzero if the angular<br />

velocity is changing, that is to say, if the particle is slowing down or speeding up as it turns.<br />

8.5 In summary<br />

1. To solve problems involving motion in two dimensions, you should break up all the forces<br />

into their components along a suitable pair of orthogonal axes, then apply Newton’s second<br />

law to each direction separately: F net,x = ma x , F net,y = ma y . It is convenient to choose your<br />

axes so that at least one of either a x or a y will be zero.<br />

2. An object thrown with some horizontal velocity component and moving under the influence<br />

of gravity alone (near the surface of the Earth) will follow a parabola in a vertical plane.<br />

This results from horizontal motion with constant velocity, and vertical motion with constant<br />

acceleration equal to −g, as described by equations (8.7).<br />

3. To analyze motion up or down an inclined plane, it is convenient to choose your axes so that<br />

the x axis lies along the surface, and the y axis is perpendicular to the surface. Then, if θ is<br />

the angle the incline makes with the horizontal, the force of gravity on the object will also<br />

make an angle θ with the negative y axis.<br />

4. Recall that the force of kinetic friction will always point in a direction opposite the motion,<br />

and will have magnitude F k = μ k F n , whereas the force of static friction will always take

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