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University Physics I - Classical Mechanics, 2019

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198 CHAPTER 9. ROTATIONAL DYNAMICS<br />

A × B<br />

A<br />

B<br />

A<br />

B<br />

B × A<br />

Figure 9.4: The “right-hand rule” to determine the direction of the cross product. Line up the first vector<br />

with the fingers, and the second vector with the flat of the hand, and the thumb will point in the correct<br />

direction. In the first drawing, we are looking at the plane formed by ⃗ A and ⃗ B from above; in the second<br />

drawing, we are looking at the plane from below, and calculating ⃗ B × ⃗ A.<br />

It follows from Eq. (9.10) that the cross-product of any vector with itself must be zero. In fact,<br />

according to Eq. (9.9), the cross product of any two vectors that are parallel to each other is zero,<br />

since in that case θ = 0, and sin 0 = 0. In this respect, the cross product is the opposite of the<br />

dot product that we introduced in Chapter 7: it is maximum when the vectors being multiplied<br />

are orthogonal, and zero when they are parallel. (And, of course, the result of ⃗ A × ⃗ B is a vector,<br />

whereas ⃗ A · ⃗B is a scalar.)<br />

Besides not being commutative, the cross product also does not have the associative property of<br />

ordinary multiplication: ⃗ A ×( ⃗ B × ⃗ C) is different from ( ⃗ A× ⃗ B)× ⃗ C. You can see this easily from the<br />

fact that, if ⃗ A = ⃗ B, the second expression will be zero, but the first one generally will be nonzero<br />

(since ⃗A × ⃗C is not parallel, but rather perpendicular to ⃗A).<br />

In spite of these oddities, the cross product is extremely useful in physics. We will use it to define<br />

the angular momentum vector ⃗ L of a particle, relative to a point O, as follows:<br />

⃗L = ⃗r × ⃗p = m⃗r × ⃗v (9.11)<br />

where ⃗r is the position vector of the particle, relative to the point O. This definition gives us<br />

a constant vector for a particle moving on a straight line, as discussed in the previous section:<br />

the magnitude of L, ⃗ according to Eq. (9.9) will be mrv sin θ, which, as shown in Fig. 9.1, does<br />

not change as the particle moves. As for the direction, it is always perpendicular to the plane<br />

containing ⃗r and ⃗v (the plane of the paper, in Fig. 9.1), and if you imagine moving ⃗v to point O,<br />

keeping it parallel to itself, and apply the right-hand rule, you will see that L ⃗ in Fig. 9.1 should<br />

point into the plane of the paper at all times.<br />

To see how the definition (9.11) works for a particle moving in a circle, consider again the situation<br />

showninFigure8.6 in the previous chapter, but now extend it to three dimensions, as in Fig. 9.5,<br />

on the next page. It is straightforward to verify that, for the direction of motion shown, the cross

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