Chapter 3 - Rolling of metals
Chapter 3 - Rolling of metals
Chapter 3 - Rolling of metals
You also want an ePaper? Increase the reach of your titles
YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.
The torque M T is equal to the total rolling<br />
load P multiplied by the effective moment<br />
arm a. Since there are two work rolls, the<br />
torque is given by<br />
M T<br />
= 2Pa<br />
…Eq.23 hf During one revolution <strong>of</strong> the top roll the<br />
resultant rolling load P moves along the<br />
circumference <strong>of</strong> a circle equal to 2ππππa.<br />
Since there are two work rolls, the work<br />
done W is equal to<br />
Work 2( 2πa)<br />
P<br />
= …Eq.24<br />
Since power is defined as the rate <strong>of</strong> doing work, i.e., 1 W = 1 J s -1 , the<br />
power (in watts) needed to operated a pair <strong>of</strong> rolls revolving at N Hz (s -1 ) in<br />
deforming metal as it flows through the roll gap is given by<br />
W 4πaPN<br />
Where P is in newtons and a is in metres.<br />
Suranaree University <strong>of</strong> Technology Tapany Udomphol<br />
Jan-Mar 2007<br />
h o<br />
= …Eq.25<br />
P<br />
P<br />
a<br />
a<br />
R<br />
R<br />
M T = Pa