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Polinomu algebra 5.lekcija

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vai sekojoˇsu sistēmu (ar, iespējams, lielāku atrisinājumu kopu)<br />

⎧<br />

⎪⎨ α2 + β2 + γ2 = − p<br />

α 2 β 2 γ 2 = q<br />

⎪⎩<br />

64<br />

α2β2 + α2γ2 + β2γ 2 = p2−4r 16 .<br />

Palīgrezultāts - Vieta formulas kubiskajiem vienādojumiem.<br />

f = X 3 + a2X 2 + a1X + a0 = (X − z1)(X − z2)(X − z3),<br />

tad un tikai tad, ja<br />

a2 = −(z1 + z2 + z3),<br />

a1 = z1z2 + z1z3 + z2z3,<br />

2<br />

a0 = −z1z2z3<br />

Saturs Sākums Beigas ◭ ◮ Atpakal¸ Aizvērt Pilns ekrāns<br />

24

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