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4. Teorema de Green

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Seja F o campo vectorial dado por<br />

F = (y 2 , x).<br />

Aplicando o <strong>Teorema</strong> <strong>de</strong> <strong>Green</strong>, obtemos:<br />

2 <br />

∂F2 ∂F1<br />

F · dr =<br />

− dydx =<br />

Γ<br />

A ∂x ∂y<br />

0<br />

2<br />

0<br />

2 <br />

= y − y 2<br />

<br />

2<br />

2<br />

dx = −2 dx = −<strong>4.</strong><br />

0<br />

0<br />

**<br />

0<br />

<br />

1 − 2y dy dx<br />

Seja A a região limitada pelas parábolas y = x 2 e y = −x 2 + 2 para x > 0.<br />

Seja F = (F1, F2) o campo vectorial<br />

.<br />

. .<br />

.<br />

.<br />

.<br />

. .<br />

F = (xy, x).<br />

Pelo <strong>Teorema</strong> <strong>de</strong> <strong>Green</strong>, temos<br />

<br />

F · dr =<br />

<br />

1 − x dxdy =<br />

Γ<br />

=<br />

A<br />

1<br />

0<br />

4 x<br />

=<br />

2<br />

<br />

y − xy<br />

−x 2 +2<br />

x 2<br />

dx =<br />

− 2<br />

3 x3 − x 2 + 2x<br />

**<br />

1 −x2 +2<br />

0 x2 1<br />

1<br />

0<br />

0<br />

.<br />

= 5<br />

6 .<br />

<br />

1 − x dy dx<br />

2x 3 − 2x 2 − 2x + 2 dx<br />

Caso A1 e A2 sejam duas regiões do plano, tal como ilustra a figura seguinte, on<strong>de</strong><br />

se possa aplicar o <strong>Teorema</strong> <strong>de</strong> <strong>Green</strong>, vamos ver que a fórmula (1) do <strong>Teorema</strong> <strong>de</strong> <strong>Green</strong><br />

vale ainda para a união A = A1 ∪ A2.<br />

5

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