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Slika - Shrani.si

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A. Juriˇ<strong>si</strong>ć in V. Batagelj: Verjetnostni račun in statistika 382<br />

✬<br />

Pokazati je mogoče (Lagrangeova funkcija),<br />

da mora biti a = −b in Φ(b) = (1 − α)/2;<br />

oziroma, če označimo b = z α/2, velja P (Z > z α/2) = α/2.<br />

Iskani interval je torej<br />

σ<br />

σ<br />

A = X − zα/2 √ in B = X + zα/2 √<br />

n n<br />

tj., z verjetnostjo 1 − α je |X − µ| < z α/2 σ<br />

√n .<br />

Od tu dobimo, da mora za to,<br />

da bo napaka manjˇsa od ε z verjetnostjo 1 − α,<br />

veljati n > ( z α/2σ<br />

ε ) 2 .<br />

✫<br />

Univerza v Ljubljani ▲<br />

❙ ▲<br />

▲<br />

● ❙ ▲<br />

▲<br />

☛ ✖<br />

▲<br />

✩<br />

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