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Integration i flere Variable

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1.4. TREDOBBELTE SUMMER OG TREDOBBELTE INTEGRALER 19<br />

Eksempel 1.13<br />

Lad f (u,v,w) = uv sin(w) for u ∈ [0,1], v ∈ [0,2] og w ∈ [0,π/2]. Så er<br />

∫ π/2<br />

( ∫ 2<br />

( ∫ 1<br />

0<br />

0<br />

0<br />

) )<br />

uv sin(w)du dv dw =<br />

= 1 2<br />

= 1 2<br />

=<br />

∫ π/2<br />

( ∫ 2<br />

0 0<br />

∫ π/2<br />

( ∫ 2<br />

0<br />

∫ π/2<br />

0<br />

∫ π/2<br />

0<br />

)<br />

v sin(w) [u 2 /2] u=1<br />

u=0 dv dw<br />

)<br />

v sin(w)dv dw<br />

0<br />

sin(w) [v 2 /2] v=2<br />

v=0 dw<br />

sin(w)dw<br />

= [−cos(w)] w=π/2<br />

w=0<br />

= 1 .<br />

Eksempel 1.14<br />

Som vi skal se i Kapitel 5 beregnes volumenet af den massive enhedskugle ved følgende tredobbelte<br />

Riemannintegral (som vil blive motiveret i det kapitel). Dermed verificeres Archimedes’ resultat:<br />

∫ 1<br />

( ∫ π<br />

( ∫ π<br />

)<br />

Vol(Enhedskuglen) =<br />

w 2 sin(u)du<br />

0 −π 0<br />

∫ 1<br />

( ∫ π<br />

= w 2 [−cos(u) ] u=π<br />

u=0 dv<br />

0 −π<br />

∫ 1<br />

( ∫ π<br />

)<br />

= 2 w 2 dv dw<br />

0 −π<br />

∫ 1<br />

= 2 w 2 [v] v=π<br />

v=−π dw<br />

0<br />

∫ 1<br />

= 4π w 2 dw<br />

0<br />

= 4π[w 3 /3] w=1<br />

w=0<br />

= 4π 3<br />

.<br />

)<br />

dv<br />

dw<br />

)<br />

dw<br />

(1.20)

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