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case, which is why usually a limiting of<br />

the wind force in operation mode is not<br />

possible.<br />

LED display 5 x 3.0 m erected<br />

Base a = 3.0 m<br />

For wind force > 8<br />

required ballast at A → 960 kg<br />

required ballast at B → no ballast<br />

A further comparison shows the influence<br />

of a reduced base on the ballast:<br />

LED display 5 x 3.0 m erected<br />

Base a = 1.50 m<br />

required ballast at A → 1920 kg<br />

required ballast at B → 820 kg<br />

Indoor riggs<br />

For indoor use horizontal compensation<br />

loads for inclination, stabilization<br />

loads and/or loads for impact of persons<br />

have to be taken into account for<br />

the bracing. (In the meantime for some<br />

exhibition halls a proof of stability for<br />

limited hall wind loads is required.<br />

These loads have to be understood as<br />

horizontal compensation loads.)<br />

The systems correspond to the outdoor<br />

riggs.<br />

Furthermore it should be noted that a<br />

frame construction only with ‘sleeveblocks’<br />

is not sufficient indoor, too. The<br />

guiding pulleys usually have so much<br />

clearance that they only have contact<br />

after tilting of the column. Additionally<br />

the stress of transverse bending would<br />

have to be verified, that results from<br />

the contact of the guiding pulleys to<br />

the truss under bending.<br />

For these riggs the minimum horizontal<br />

load for unintentional inclination is:<br />

H = V / 200 and<br />

V / 100 simplified as V / 50<br />

It should be kept in mind that columns<br />

on base plates with small dimensions<br />

stand on their own but get already<br />

instable at a slight addition of horizontal<br />

loads.<br />

Example<br />

Columns: truss w= 35 cm on base<br />

plate 40 x 40 cm:<br />

with h = 3.50 m<br />

average height of the rig<br />

by crowd:<br />

Hs > 0.5 kN at h = 1,0 m<br />

payload and self weight:<br />

V = 2.0 /2 = 1,0 kN per column<br />

with H = 1.0 / 50 = 0.02 kN<br />

A. → Mtilt = 3.5 x 0,02 = 0.07 kNm<br />

by crowd<br />

Hs > 0.5 kN in Höhe h = 1.0 m<br />

B. → Mtilt = 0.5 x 1.0 = 0.50 kNm<br />

the tilting moment has to be smaller<br />

than the stablity moment<br />

with safety of 1.3:<br />

Mtilt x 1.3 < V x 0.18 m<br />

A: 0.07 x 1.3 = 0.091 < 1.0 x 0.18 = 0.18<br />

B. (0.07+0.5) x 1.3 = 0.74 >> 0.18<br />

Four times below the safety!<br />

Conclusion: Columns that are restrained<br />

at the base have to be designed<br />

with sufficiently stable basement with<br />

outriggers or with the possibility of ballasting<br />

or with a plugged and ‘strong’<br />

base plate.<br />

GROUND SUPPORT<br />

Autoren:<br />

Frank Bastians, Stefan Krasenbrink, Jan Keppler, Ralf-Harald vom Felde.<br />

Weitere Informationen gibt es von den Autoren unter:<br />

www.krasenbrink-bastians.de sowie www.vom-felde.de<br />

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