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Ad Quadratum Construction and Study of the Regular Polyhedra

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104<br />

Note also that three such pentagrams meet at each <strong>of</strong> <strong>the</strong> 20 vertices <strong>of</strong> <strong>the</strong> convex<br />

dodecahedron to yield a GSD.<br />

So far, by means <strong>of</strong> <strong>the</strong> three mutually perpendicular golden rectangles we have<br />

established <strong>the</strong> convex icosahedron <strong>and</strong> dodecahedron as well as <strong>the</strong> four stellated<br />

regular polyhedra.<br />

The octahedron has been implicitly established when we constructed adquadratum<br />

<strong>the</strong> three mutually perpendicular planes within <strong>the</strong> sphere. Their mutual<br />

intersections two at a time with <strong>the</strong> sphere at 6 different points are <strong>the</strong> vertices <strong>of</strong><br />

<strong>the</strong> octahedron.<br />

For <strong>the</strong> cube, on one <strong>of</strong> <strong>the</strong> three planes we draw through <strong>the</strong> center <strong>of</strong> <strong>the</strong> sphere<br />

two diameters forming angle C ˆ<br />

i.<br />

Four vertices are <strong>the</strong>reby determined at <strong>the</strong><br />

contact point with <strong>the</strong> sphere. Drawing circles <strong>of</strong> radius equal to <strong>the</strong> adquadratum<br />

value <strong>of</strong> <strong>the</strong> cube edge on <strong>the</strong> sphere from each <strong>of</strong> <strong>the</strong>se four vertices will yield<br />

four new vertices at <strong>the</strong>ir intersection. The total <strong>of</strong> 8 vertices is <strong>the</strong>n available for<br />

<strong>the</strong> cube.<br />

The tetrahedron will <strong>the</strong>n be easily constructed by selecting one <strong>of</strong> <strong>the</strong> cube<br />

vertices as a starting point <strong>and</strong> fur<strong>the</strong>r selecting its three second immediate<br />

neighbors <strong>and</strong> joining <strong>the</strong>se 4 vertices toge<strong>the</strong>r.<br />

b. By Individual <strong>Polyhedra</strong><br />

The three golden rectangles approach yields a top-down generation <strong>of</strong> <strong>the</strong> regular<br />

polyhedra so to speak. We go from <strong>the</strong> complex to <strong>the</strong> simple, from <strong>the</strong><br />

icosahedron <strong>and</strong> dodecahedron <strong>and</strong> <strong>the</strong>ir stellated forms to <strong>the</strong> cube <strong>and</strong> <strong>the</strong><br />

tetrahedron. In <strong>the</strong> present method, we go from <strong>the</strong> simplest to <strong>the</strong> more complex,<br />

starting with <strong>the</strong> individual tetrahedron. We make no direct reference to <strong>the</strong><br />

golden rectangle structure.<br />

Given are <strong>the</strong> sphere <strong>of</strong> Radius R <strong>and</strong> <strong>the</strong> adquadratum diagram providing us with<br />

<strong>the</strong> internal angle <strong>and</strong> <strong>the</strong>refore <strong>the</strong> edge <strong>of</strong> each polyhedron inscribed in <strong>the</strong><br />

sphere <strong>of</strong> radius R.<br />

For <strong>the</strong> Tetrahedron, pick a point at r<strong>and</strong>om on <strong>the</strong> sphere. One can imagine<br />

doing this ei<strong>the</strong>r externally or internally to <strong>the</strong> sphere. From that point as center,<br />

draw on <strong>the</strong> surface <strong>of</strong> <strong>the</strong> sphere <strong>the</strong> circle having for radius <strong>the</strong> chord <strong>of</strong> <strong>the</strong><br />

tetrahedron internal angle (edge <strong>of</strong> <strong>the</strong> tetrahedron) as given on <strong>the</strong> adquadratum<br />

diagram. From ano<strong>the</strong>r point at r<strong>and</strong>om on this circle <strong>and</strong> with <strong>the</strong> same compass<br />

opening, draw ano<strong>the</strong>r circle on <strong>the</strong> sphere. It will cut <strong>the</strong> first circle at two<br />

points. These <strong>and</strong> <strong>the</strong> two previous points are <strong>the</strong> vertices <strong>of</strong> <strong>the</strong> tetrahedron. The<br />

six straight line segments joining <strong>the</strong> 4 vertices toge<strong>the</strong>r are <strong>the</strong> edges <strong>of</strong> <strong>the</strong><br />

tetrahedron. Joining <strong>the</strong> vertices to <strong>the</strong> center <strong>of</strong> <strong>the</strong> sphere gives form to <strong>the</strong><br />

Maraldian pyramids <strong>of</strong> <strong>the</strong> tetrahedron.

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