Ad Quadratum Construction and Study of the Regular Polyhedra
Ad Quadratum Construction and Study of the Regular Polyhedra
Ad Quadratum Construction and Study of the Regular Polyhedra
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47<br />
We shall now determine <strong>the</strong> diameter <strong>of</strong> <strong>the</strong> circumsphere <strong>of</strong> <strong>the</strong> new figure <strong>and</strong> <strong>the</strong> side<br />
<strong>of</strong> <strong>the</strong> cube circumscribing it.<br />
A top view <strong>of</strong> <strong>the</strong> stella octangula (fig. 33) shows that <strong>the</strong> edge <strong>of</strong> one <strong>of</strong> <strong>the</strong> typical<br />
pyramids (OC) is equal in length to <strong>the</strong> edge <strong>of</strong> <strong>the</strong> original octahedron(DE). Therefore<br />
<strong>the</strong> construction <strong>of</strong> <strong>the</strong> pyramids is straightforward. From <strong>the</strong> <strong>Ad</strong> <strong>Quadratum</strong> diagram<br />
measure a, <strong>the</strong> edge <strong>of</strong> <strong>the</strong> octahedron. Draw a circle (fig. 34) <strong>of</strong> radius a <strong>and</strong> measure a<br />
with a compass along <strong>the</strong> circumference three times. Draw chords <strong>and</strong> radii to obtain a<br />
half hexagon. This is <strong>the</strong> development <strong>of</strong> <strong>the</strong> pyramid. Cut out <strong>and</strong> fold. Repeat <strong>the</strong><br />
operation 8 times (one for each pyramid). They can now be assembled to form <strong>the</strong> stella<br />
octangula.<br />
Referring to fig. 33, if DE=a is <strong>the</strong> edge <strong>of</strong> octahedron, <strong>the</strong> edge <strong>of</strong> pyramid OC also<br />
equals a, <strong>the</strong>n <strong>the</strong> edge <strong>of</strong> circumscribing cube is<br />
AB AO 2 OB 2 2a 2<br />
AB a 2<br />
Therefore, <strong>the</strong> circumsphere radius which is half <strong>the</strong> cube diagonal will be:<br />
AB<br />
2<br />
3 <br />
a 2<br />
2<br />
3 a 3<br />
2<br />
The relationship between dihedral angles <strong>of</strong> <strong>the</strong> stella octangula <strong>and</strong> <strong>the</strong> original<br />
octahedron can readily be written.<br />
We have:<br />
O ˆ<br />
D ˆ C i<br />
<strong>and</strong> ˆ<br />
T D ˆ<br />
T i ˆ<br />
T D ˆ<br />
O D<br />
or ˆ<br />
O D ˆ<br />
T D<br />
<br />
ˆ<br />
T i<br />
Of course, <strong>the</strong> stella octangula can also be constructed from two intersecting internal<br />
tetrahedra.<br />
2. The Process <strong>of</strong> Stellation