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Ad Quadratum Construction and Study of the Regular Polyhedra

Ad Quadratum Construction and Study of the Regular Polyhedra

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47<br />

We shall now determine <strong>the</strong> diameter <strong>of</strong> <strong>the</strong> circumsphere <strong>of</strong> <strong>the</strong> new figure <strong>and</strong> <strong>the</strong> side<br />

<strong>of</strong> <strong>the</strong> cube circumscribing it.<br />

A top view <strong>of</strong> <strong>the</strong> stella octangula (fig. 33) shows that <strong>the</strong> edge <strong>of</strong> one <strong>of</strong> <strong>the</strong> typical<br />

pyramids (OC) is equal in length to <strong>the</strong> edge <strong>of</strong> <strong>the</strong> original octahedron(DE). Therefore<br />

<strong>the</strong> construction <strong>of</strong> <strong>the</strong> pyramids is straightforward. From <strong>the</strong> <strong>Ad</strong> <strong>Quadratum</strong> diagram<br />

measure a, <strong>the</strong> edge <strong>of</strong> <strong>the</strong> octahedron. Draw a circle (fig. 34) <strong>of</strong> radius a <strong>and</strong> measure a<br />

with a compass along <strong>the</strong> circumference three times. Draw chords <strong>and</strong> radii to obtain a<br />

half hexagon. This is <strong>the</strong> development <strong>of</strong> <strong>the</strong> pyramid. Cut out <strong>and</strong> fold. Repeat <strong>the</strong><br />

operation 8 times (one for each pyramid). They can now be assembled to form <strong>the</strong> stella<br />

octangula.<br />

Referring to fig. 33, if DE=a is <strong>the</strong> edge <strong>of</strong> octahedron, <strong>the</strong> edge <strong>of</strong> pyramid OC also<br />

equals a, <strong>the</strong>n <strong>the</strong> edge <strong>of</strong> circumscribing cube is<br />

AB AO 2 OB 2 2a 2<br />

AB a 2<br />

Therefore, <strong>the</strong> circumsphere radius which is half <strong>the</strong> cube diagonal will be:<br />

AB<br />

2<br />

3 <br />

a 2<br />

2<br />

3 a 3<br />

2<br />

The relationship between dihedral angles <strong>of</strong> <strong>the</strong> stella octangula <strong>and</strong> <strong>the</strong> original<br />

octahedron can readily be written.<br />

We have:<br />

O ˆ<br />

D ˆ C i<br />

<strong>and</strong> ˆ<br />

T D ˆ<br />

T i ˆ<br />

T D ˆ<br />

O D<br />

or ˆ<br />

O D ˆ<br />

T D<br />

<br />

ˆ<br />

T i<br />

Of course, <strong>the</strong> stella octangula can also be constructed from two intersecting internal<br />

tetrahedra.<br />

2. The Process <strong>of</strong> Stellation

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