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Ad Quadratum Construction and Study of the Regular Polyhedra

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15<br />

A simple way <strong>of</strong> constructing each individual pyramid is to plot four times C ˆ i along a<br />

great circle <strong>of</strong> <strong>the</strong> circumsphere (fig. 11). When cut <strong>and</strong> folded, we obtain <strong>the</strong> pyramid<br />

(including <strong>the</strong> arc <strong>of</strong> <strong>the</strong> great circle subtended by <strong>the</strong> cube edge). Six such constructions<br />

will yield <strong>the</strong> cube.<br />

The <strong>Ad</strong> <strong>Quadratum</strong> <strong>Construction</strong><br />

The <strong>Ad</strong> <strong>Quadratum</strong> construction begins with <strong>the</strong> construction <strong>of</strong> a double square each <strong>of</strong><br />

side unity (fig. 12).<br />

We <strong>the</strong>refore begin with a circle <strong>of</strong> unit radius to which we add two intersecting <strong>and</strong><br />

equal circles, centered at <strong>the</strong> extremity <strong>of</strong> a diameter, respectively, so as to form a double<br />

vesica. The intersection <strong>of</strong> <strong>the</strong> center line <strong>and</strong> <strong>of</strong> <strong>the</strong> tangents to <strong>the</strong> circles with <strong>the</strong><br />

secants through <strong>the</strong> 2 vesicas determine <strong>the</strong> double squares: A B O G.<br />

It is on <strong>the</strong> basis <strong>of</strong> <strong>the</strong>se two squares that <strong>the</strong> construction evolves (fig. 13). Toge<strong>the</strong>r<br />

<strong>the</strong>y form a rectangle ABOG with sides equal to 1 <strong>and</strong> 2 respectively.<br />

Diagonal GB 5 .<br />

We can already note in passing that tan A ˆ G B 2<br />

<strong>and</strong> <strong>the</strong>refore that A ˆ G B A ˆ O B ˆ I i , <strong>the</strong> internal angle <strong>of</strong> <strong>the</strong> icosahedron.<br />

Now swing GB down in <strong>the</strong> extension <strong>of</strong> GA to point D.<br />

In triangle OGD, GD 5, GO 2.<br />

Therefore DO 3.<br />

And <strong>the</strong>refore,<br />

G ˆ D O D ˆ O B ˆ D i ,<br />

<strong>the</strong> internal angle <strong>of</strong> <strong>the</strong> dodecahedron, since<br />

sinG ˆ D O GO 2<br />

<br />

DO 3 .<br />

Now describe <strong>the</strong> circle centered at O with radius OD <strong>and</strong> extend AB to S; OB to R <strong>and</strong><br />

U; OG to V <strong>and</strong> OA to W, where <strong>the</strong>se extensions intercept <strong>the</strong> circle.<br />

Then draw OS.<br />

It will be seen that in triangle BOS,<br />

cosB ˆ<br />

O S 1<br />

3<br />

<strong>and</strong> <strong>the</strong>refore B ˆ<br />

O S ˆ<br />

C i , <strong>the</strong> internal angle <strong>of</strong> <strong>the</strong> cube.

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