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Ad Quadratum Construction and Study of the Regular Polyhedra

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Dodecahedron:<br />

11<br />

For <strong>the</strong> dodecahedron, we proceed as for <strong>the</strong> cube calling in this case its internal angle<br />

D ˆ i , <strong>the</strong> angle between two consecutive diagonals. These diagonals constitute <strong>the</strong> sides <strong>of</strong><br />

a triangle, itself side <strong>of</strong> a pyramid with apex at <strong>the</strong> center <strong>of</strong> <strong>the</strong> circumsphere <strong>and</strong> having<br />

for base a regular pentagon, face <strong>of</strong> <strong>the</strong> dodecahedron.<br />

Though nei<strong>the</strong>r equal nor similar, <strong>the</strong> isosceles triangle, face <strong>of</strong> <strong>the</strong> pyramid just<br />

described, has <strong>the</strong> same geometry as that for <strong>the</strong> cube previously examined (fig. 7). We<br />

can <strong>the</strong>refore write:<br />

ˆ<br />

2<br />

ˆ<br />

2 Di<br />

a<br />

cos Di<br />

1<br />

2sin<br />

1<br />

2<br />

2 2R<br />

Here, however:<br />

<strong>and</strong> <strong>the</strong>refore:<br />

or:<br />

a 3<br />

3<br />

5 1R<br />

a 2 1<br />

62 5R<br />

3 2<br />

a 2<br />

5<br />

2 1<br />

2R 3<br />

cos ˆ D i 1 1 5 <br />

<br />

<br />

<br />

5<br />

3<br />

3<br />

In triangle ACH we <strong>the</strong>refore have:<br />

AC R; CH 5<br />

3 R; <strong>and</strong> AH 2 AC 2 CH 2 ,<br />

or: AH 2 R 2 5<br />

9 R2 R 2 1 5 <br />

R<br />

9<br />

24 <br />

9<br />

<br />

AH <br />

<br />

2<br />

R ;<br />

3<br />

where from sin ˆ D i AH 2<br />

<br />

AC 3<br />

Icosahedron:<br />

sin ˆ<br />

D i 2<br />

3<br />

Proceeding similarly for <strong>the</strong> icosahedron, we have:<br />

cos ˆ<br />

2 I ˆ i<br />

I i 12sin<br />

2<br />

1 a 2<br />

2R 2 ,

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