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Solving Differential Equations in Terms of Bessel Functions

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38 CHAPTER 2. TRANSFORMATIONS<br />

Lemma 2.12 Let L,M,∈ K[∂] be two differential operators such that M r<br />

−→E L<br />

and let e be an exponent <strong>of</strong> M at the po<strong>in</strong>t p. Furthermore, let r have the series<br />

representation<br />

r =<br />

∞<br />

∑ rit<br />

i=m<br />

i p, m ∈ Z,m ≤ −1.<br />

Then e + ∑ −1<br />

i=m riti+1 p is an exponent <strong>of</strong> L at p.<br />

Pro<strong>of</strong>. Let t be the local parameter tp. S<strong>in</strong>ce e is an exponent, M has a solution <strong>of</strong><br />

the form<br />

<br />

e<br />

y = exp<br />

t dt<br />

<br />

S,<br />

for some Puiseux series S ∈ k((t))[ln(t)]. The exp-product converts this solution<br />

<strong>in</strong>to<br />

<br />

z = exp<br />

<br />

e<br />

rdt exp<br />

t dt<br />

<br />

S.<br />

In order to determ<strong>in</strong>e the exponent at p we have to rewrite this expression <strong>in</strong>to<br />

the form (1.26). We have to handle the positive and negative powers <strong>of</strong> t <strong>in</strong> r<br />

separately. For the power series part ¯r = ∑ ∞ i=0 rit i we get<br />

With exp(x) = ∑ ∞ i=0 xi<br />

i!<br />

<br />

exp<br />

<br />

exp<br />

<br />

∞<br />

ri<br />

¯r dt = exp ∑<br />

i=0 i + 1 ti+1<br />

<br />

.<br />

we can rewrite this as a power series <strong>in</strong> t:<br />

<br />

¯r dt =<br />

=<br />

∞<br />

∑<br />

i=0<br />

∞<br />

∑<br />

i=0<br />

<br />

∞ 1<br />

i! ∑<br />

j=0<br />

i r j j+1<br />

t<br />

j + 1<br />

ait i with ai ∈ k,a0 = 1.<br />

The negative powers <strong>of</strong> t <strong>in</strong> the series expansion <strong>of</strong> r become a part <strong>of</strong> the<br />

exponent:<br />

<br />

<br />

exp<br />

−1<br />

∑ rit<br />

i=m<br />

i <br />

<br />

1<br />

dt = exp<br />

t<br />

Comb<strong>in</strong><strong>in</strong>g the two results we get<br />

z = exp<br />

<br />

<br />

1<br />

t<br />

e +<br />

−1<br />

∑ rit<br />

i=m<br />

i+1<br />

−1<br />

∑ rit<br />

i=m<br />

i+1 <br />

dt .<br />

<br />

dt<br />

<br />

¯S,

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