Solving Differential Equations in Terms of Bessel Functions
Solving Differential Equations in Terms of Bessel Functions
Solving Differential Equations in Terms of Bessel Functions
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50 CHAPTER 3. SOLVING IN TERMS OF BESSEL FUNCTIONS<br />
Example 3.2<br />
As <strong>in</strong> Example 2.11 we start with the modified <strong>Bessel</strong> operator LB with ν = 2. We<br />
do the same change <strong>of</strong> variables with<br />
f =<br />
2(x − 1)(x − 2)2<br />
(x − 3) 2<br />
and get the operator<br />
> LB:=xˆ2*Dxˆ2+x*Dx-(xˆ2+2ˆ2):<br />
> f:=2*(x-1)*(x-2)ˆ2/(x-3)ˆ2:<br />
> L:=changeOfVars(LB,f);<br />
= 2x3 − 10x 2 + 16x − 8<br />
x 2 − 6x + 9<br />
L :=(x − 2) 3 x 2 − 7x + 8 (x − 3) 6 (x − 1) 3 ∂ 2 +<br />
4 3 2 5 2 2<br />
x − 14x + 55x − 84x + 46 (x − 3) (x − 1) (x − 2) ∂−<br />
4 x 2 3<br />
<br />
− 7x + 8 x 6 − 10x 5 + 42x 4 − 100x 3 + 158x 2 <br />
− 172x + 97<br />
(x − 2)(x − 1)<br />
The s<strong>in</strong>gularities <strong>of</strong> this operator are 1,2,3,∞, 7 2 + 1 √<br />
7<br />
2 17 and 2 − 1 √<br />
2 17. We already<br />
discovered <strong>in</strong> Example 2.11 that the latter two s<strong>in</strong>gularities are apparent, 1<br />
and 2 are the regular s<strong>in</strong>gularities, and 3 and ∞ are irregular s<strong>in</strong>gularities.<br />
We will now use part (b) <strong>of</strong> the theorem to f<strong>in</strong>d f . In order to do this we<br />
compute the generalized exponent at x = 3 us<strong>in</strong>g Maple:<br />
> gen exp(L,t,x=3);<br />
[[− 8 10<br />
8 10<br />
− + 1,t = x − 3],[ + + 1,t = x − 3]] (3.9)<br />
t2 t t2 t<br />
The exponent difference is<br />
∆(L,3) = − 16<br />
t 2 3<br />
− 20<br />
.<br />
t3<br />
If we divide ∆(L,3) by two and each coefficient by its correspond<strong>in</strong>g degree we<br />
get<br />
f3 = − 4<br />
t 2 3<br />
− 10<br />
.<br />
t3<br />
This will be the polar part correspond<strong>in</strong>g to t3 <strong>in</strong> the partial fraction decomposition<br />
<strong>of</strong> f .<br />
We do the same computations at the po<strong>in</strong>t x = ∞:<br />
> gen exp(L,t,x=<strong>in</strong>f<strong>in</strong>ity);<br />
[[− 2<br />
t<br />
1 1<br />
+ ,t =<br />
2 x ],[2<br />
t<br />
+ 1<br />
2<br />
1<br />
,t = ]] (3.10)<br />
x