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Teaching Modern Physics - QuarkNet - Fermilab

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For path A…<br />

The cathode ray only interacts with the electric field<br />

so:<br />

Fc = FE<br />

(mv 2 )/r = qE<br />

For path C…<br />

The cathode ray only interacts with the magnetic<br />

field so:<br />

Fc =FB<br />

(mv 2 )/r = qvB<br />

q/m = v/(Br)<br />

41

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