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3D DISCRETE DISLOCATION DYNAMICS APPLIED TO ... - NUMODIS

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2.2 Computation of stresses and displacements of dislocations 15<br />

includes four contributions:<br />

(i) the force due to the internal stress field produced by all the other dislocation segments in the<br />

simulation volume except by two neighboring segments and the considered segment itself<br />

(ii) the force due to applied stress fields<br />

(iii) the force due to the line tension<br />

(iv) the force due to the Peierls stress<br />

The forces due to atomistic-level interactions, such as dragging forces by solute atoms or jogs, are not<br />

treated explicitly. They can be included implicitly, however, by modifying the motion rule which de-<br />

fines the relation between the glide velocity and the effective shear stress of a segment (see Sec. 2.3).<br />

Internal stresses<br />

To compute the internal stresses at the center of a segment, the expression of the stress field of a<br />

single finite straight segment is required. This problem has been addressed by Li ([Li 64]). Li has<br />

found an interesting fact from the stress solution of an angular dislocation made of two semi-infinite<br />

dislocations joined together at one point. According to Li, the stress field of an angular dislocation<br />

is the sum of the stress fields of each dislocation arm, i.e., a semi-infinite dislocation. Although the<br />

stress field of a semi-infinite dislocation does not obey the equations of equilibrium, the sum of the<br />

stress fields of two semi-infinite dislocations satisfies the equilibrium.<br />

If a semi-infinite dislocation lies in the positive z axis running into the origin, O, the stress field<br />

produced at a point r(x,y,z) has the following components ([Li 64]).<br />

σxx(r) = −bxy−byx<br />

r(r−z) − x2 (bxy−byx)(2r−z))<br />

r 3 (r−z) 2<br />

σyy(r) = bxy+byx<br />

r(r−z) − y2 (bxy−byx)(2r−z))<br />

r 3 (r−z) 2<br />

σzz(r) = z(bxy−byx)<br />

r 3<br />

σyz(r) = y(bxy−byx)<br />

r 3<br />

σzx(r) = x(bxy−byx)<br />

r 3<br />

σxy(r) = bxx−byy<br />

r(r−z)<br />

− 2ν(bxy−byx)<br />

r(r−z)<br />

− νbx<br />

r<br />

+ νby<br />

r<br />

+ (1−ν)bzx<br />

r(r−z)<br />

− (1−ν)bzy<br />

r(r−z)<br />

− xy(bxy−byx)(2r−z)<br />

r 3 (r−z) 2<br />

In Eq. 2.2, the stresses are given in unit of µ/4π(1 − ν) with µ and ν being the shear modulus and<br />

the Poisson ratio respectively. r is the distance to the point r(x,y,z) as shown in Fig. 2.4. The<br />

stress field of a dislocation segment lying on the z axis running from z2 into z1 is obtained from<br />

(2.2)

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