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The Picard-Lefschetz theory of complexified Morse functions 1 ...

The Picard-Lefschetz theory of complexified Morse functions 1 ...

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58 Joe Johns<br />

We, on the other hand, identify<br />

f −1<br />

2 ([c2 − 1/2, c2 + 1/2]) ∩ (k 2 ) −1 ([4(r/2) 2 , 4r 2 ]) with D [r/2,r](ν ∗ K+) ∼ = S 1 × D 2 [r/2,r]<br />

in just one step using Φ 2 . To compare our approach to Milnor’s we express Φ 2<br />

in two steps as follows. Recall that lemma 4.1 says Φ 2 = ρ0 ◦ Φ 2 , where Φ2<br />

is radial symplectic flow to π −1<br />

2 (0) \ {0}. This implies that Φ2 can be expressed<br />

in two steps as symplectic flow to π −1<br />

2 (−1/2), followed by Φ2 −1/2<br />

. Lemma 8.3<br />

below shows that symplectic flow along the real part and gradient flow agree up to<br />

reparameterization, so that implies that the first step <strong>of</strong> Milnor’s approach agrees with<br />

our first step (up to isotopy). As for comparing Φ −1/2 and η, recall that for each<br />

x ∈ f −1<br />

2 (c2 − 1/2) ∩ (k 2 ) −1 ([4(r/2) 2 , 4r 2 ]), we have<br />

for some<br />

<strong>The</strong>n since<br />

and<br />

it follows that Φ 2 −1/3<br />

Φ2(x) = (u, 0) + i(0,λv)<br />

(u,λv) ∈ S 1 × D 2 [r/2,r]<br />

η(u,θv) = (cosh θu, sinh θv)<br />

k2((cosh θu, 0) + (0, sinh θv)) = sinh 2 θ + 2 sinh θ<br />

(Above, ϕ is the inverse <strong>of</strong> this map.)<br />

and η differ only by a radial diffeomorphism<br />

θ ↦→ λ = sinh 2 θ + 2 sinh θ.<br />

Here is the precise statement and pro<strong>of</strong> <strong>of</strong> the claim in the last remark concerning<br />

symplectic transport on the real part.<br />

Lemma 8.3 Let π : E −→ C be a symplectic <strong>Lefschetz</strong> fibration, where E is equipped<br />

with symplectic structure ω, such that the regular fibers <strong>of</strong> π are symplectic, and J<br />

is an almost complex structure on E compatible with ω such that π∗(Jv) = iJπ∗(v).<br />

Suppose E has an anti-symplectic, anti-complex involution<br />

that is,<br />

ι: E −→ E,<br />

ι 2 = id<br />

ι ∗ ω = −ω

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