19.07.2013 Views

the production of thymoquinone from thymol and carvacrol

the production of thymoquinone from thymol and carvacrol

the production of thymoquinone from thymol and carvacrol

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

not determined by orbital energy alone. In chromium it can be shown that <strong>the</strong> 4s orbital<br />

energy is still below <strong>the</strong> 3d which suggests a configuration [Ar] 3d 4 4s 2 . Due to <strong>the</strong> effect<br />

<strong>of</strong> electronic repulsion between <strong>the</strong> outer electrons <strong>the</strong> actual configuration becomes<br />

[Ar] 3d 5 4s 1 where all <strong>the</strong> electrons in <strong>the</strong> outer orbitals are unpaired. The interesting<br />

thing about transition metals is <strong>the</strong> electrons <strong>the</strong>y use to combine with o<strong>the</strong>r elements<br />

(valence electrons) are present in more than one shell. This is <strong>the</strong> reason why <strong>the</strong>y <strong>of</strong>ten<br />

exhibit several common oxidation states. The elements in this group can have different<br />

oxidation states which makes <strong>the</strong>m useful as catalyst.<br />

Cr has only one electron in its 4s sub-shells because <strong>the</strong> o<strong>the</strong>r electron is used to<br />

make a half full 3d sub-shell which is more stable. The same argument goes for Cu,<br />

which makes a full 3d sub-shell. When <strong>the</strong> transition metals become ions <strong>the</strong>y lose <strong>the</strong>ir<br />

4s electrons first. Fe for example loses 3 electrons to become a Fe 3+ ion. It will <strong>the</strong>refore<br />

lose 2 4s electrons <strong>and</strong> one 3d electron.The final configuration <strong>of</strong> <strong>the</strong> metal ion is<br />

stabilized if <strong>the</strong> electron configuration includes ei<strong>the</strong>r half-full or full orbitals. The<br />

electrons may be shuffled between <strong>the</strong> s <strong>and</strong> d orbitals to maintain <strong>the</strong> most stable form.<br />

The difference in energy between <strong>the</strong> second <strong>and</strong> third shells is less than<br />

between <strong>the</strong> first <strong>and</strong> second. By <strong>the</strong> time <strong>the</strong> fourth shell is reached, <strong>the</strong>re is, in fact an<br />

overlap between <strong>the</strong> third <strong>and</strong> fourth shells. In o<strong>the</strong>r words, <strong>from</strong> sc<strong>and</strong>ium onwards, <strong>the</strong><br />

orbitals <strong>of</strong> highest energy in <strong>the</strong> third shell (<strong>the</strong> 3d orbital) have higher energy than<br />

those <strong>of</strong> <strong>the</strong> lowest energy in <strong>the</strong> fourth shell (<strong>the</strong> 4s orbital). Hence, when writing <strong>the</strong><br />

electronic configurations <strong>of</strong> <strong>the</strong>se ‘d’ block elements we fill <strong>the</strong> 4s <strong>the</strong>n <strong>the</strong> 3d orbitals.<br />

Exceptions do occur for Cr [Ar] 4s 1 3d 5 <strong>and</strong> Cu [Ar] 4s 1 3d 10 .This can be explained by<br />

<strong>the</strong> extra stability <strong>of</strong>fered by full <strong>and</strong> half-filled ‘d’ orbitals.<br />

12

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!