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The computation of turbulent natural convection flows - Turbulence ...

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107<br />

+A1y ∗ + by∗2<br />

<br />

2<br />

+ bµy ∗2<br />

∗ y<br />

3 − y∗ <br />

υ<br />

2<br />

µυU1 = C1<br />

2 y∗2<br />

Prυy<br />

+ bbµ<br />

∗3<br />

µυ<br />

<br />

Cth1y ∗2<br />

+ bb 2 Prυy<br />

µ<br />

∗3 <br />

Cth1<br />

6µυ<br />

+ bb 2 Prυy<br />

µ<br />

∗3<br />

6µυ<br />

+ bµA1y ∗<br />

∗ y<br />

2 −y∗ <br />

υ<br />

(Θwall −Θref)+<br />

[C1 +b(Θwall −Θref)]<br />

20 − (Cth1y∗ υ −2Ath1)<br />

10<br />

12 y∗3 − (3Cth1y∗ υ −2Ath1)<br />

10<br />

<br />

(Cth1y∗ υ −4Ath1)y ∗ υ<br />

In the fully <strong>turbulent</strong> region y ∗ > y ∗ υ<br />

4<br />

Prυy ∗<br />

3µυ<br />

Cth1y ∗<br />

y ∗ − Ath1y ∗ υ<br />

y ∗2<br />

y ∗ +Ath1y ∗2<br />

υ<br />

<br />

<br />

3<br />

4 +Ath1<br />

<br />

<br />

(4.56)<br />

the momentum equation is written as:<br />

∂<br />

∂y∗ <br />

(µ+µt) ∂U2<br />

∂y∗ <br />

= C2 +b(Θ2 −Θref) (4.57)<br />

First the equation for Θ2 from the thermal analytical wall function (equa-<br />

tion 4.38) is substituted into the above equation. <strong>The</strong>n we assume that the<br />

<strong>turbulent</strong> viscosity varies linearly across the fully <strong>turbulent</strong> region, according<br />

to equation 4.20. After a first integration, the wall-parallel velocity gradient<br />

across the fully <strong>turbulent</strong> region <strong>of</strong> the near wall control volume is:<br />

µυ<br />

∂U2<br />

=<br />

∂y∗ C2<br />

[1+α(y ∗ −y ∗ υ )]y∗ +<br />

+ b PrυCth2<br />

2µυαt<br />

+ b M<br />

αt<br />

y ∗2<br />

[1+α(y ∗ −y ∗ υ<br />

A2<br />

[1+α(y ∗ −y∗ υ )] +b(R+Θwall −Θref)<br />

[1+α(y ∗−y ∗ y∗<br />

υ )]<br />

)] −b Prυ<br />

µυαt<br />

YT<br />

[1+α(y ∗ −y ∗ υ )] (lnYT −1)−<br />

y ∗<br />

Cth2y ∗ υ<br />

[1+α(y ∗−y ∗ υ )]<br />

bbµRµy ∗<br />

[1+α(y ∗ −y ∗ υ )]<br />

(4.58)<br />

<strong>The</strong> parameters, M, R and Rµ, are calculated by imposing the appropriate<br />

boundary conditions.<br />

Let<br />

Y = [1+α(y ∗ −y ∗ υ)] (4.59)

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